Answer:
a) a = 7.72 m / s², N = 19.9 N and b) F = 25.5 N
Explanation:
To solve this problem we will use Newton's second law, let's set a reference system with an axis parallel to the plane and gold perpendicular axis. Let's break down the weight (W)
sin52 = Wx / W
cos52 = Wy / W
Wx = W sin52
Wy = w cos 52
Let's write them equations
X axis
Wx = ma
Y Axis
N-Wy = 0
N = Wy
a) Let's calculate the acceleration
a = W sin52 / m = mg sin 52 / m
a = g sin 52
a = 9.8 sin52
a = 7.72 m / s²
The force of the ramp is normal
N = Wy = mg cos 52
N = 3.3 9.8 cos 52
N = 19.9 N
b) For the block to move at constant speed the sum of force on the axis must be zero,
F - Wx = 0
F = Wx
F = mg sin52
F = 3.3 9.8 sin 52
F = 25.5 N
Parallel to the plane and going up
Answer:
The distance is 
Explanation:
From the question we are told that
The smallest shift is 
Generally a grid unit is 
of an arcsec
This implies that 0.2 grid unit is 
The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as
substituting values
Note 
So 
Answer:
I₂ = 2.13 x 10⁻⁸ W/m²
Explanation:
given,
increase in sound level = 28.1 dB
frequency of the sound = 250 Hz
intensity = 3.3 x 10⁻¹¹ W/m²
Intensity delivered = ?
the difference of intensity level is give as
I₂ = 645.65 I₁
I₂ = 645.65 x 3.3 x 10⁻¹¹
I₂ = 2.13 x 10⁻⁸ W/m²
I found the Hydrolic system, im not sire if its helpful or not. I could only find that one, sorry if it doesn't help but I hope it does ^-^
Answer:
The uncertainty in momentum changes by a factor of 1/2.
Explanation:
By Heisenberg's uncertainty principle, ΔpΔx ≥ h/2π where Δp = uncertainty in momentum and Δx = uncertainty in position = 0.2 nm. The uncertainty in momentum is thus Δp ≥ h/2πΔx. If the uncertainty in position is doubled, that is Δx₁ = 2Δx = 0.4 nm, the uncertainty in momentum Δp₁ now becomes Δp₁ ≥ h/2πΔx₁ = h/2π(2Δx) = (h/2πΔx)/2 = Δp/2.
So, the uncertainty in momentum changes by a factor of 1/2.
