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3 years ago

The variable that stays constant when using the combined gas law is

Chemistry

1 answer:

Damm [24]3 years ago

3 0

The variable that stays constant is the number of molecules.

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3 years ago

G.com what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume

tiny-mole [99]

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3 years ago

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4 years ago

Procaine hydrochloride ( MW = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which ha

fenix001 [56]

Answer:

$\boxed{\text{2.274 mol/L}}$

Explanation:

$b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}$

Assume 1 kg water.

1. Moles of P.HCl

Then we have 4.666 mol of P.HCl

2. Mass of P.HCl

n = 4.666 mol × 272.77 g/mol = 1271.1 g

3. Total mass of solution

m = 1000 g + 1271.1 g = 2271.1 g solution

4. Volume of solution

$V = \text{2271.1 g} \times \dfrac{\text{1 mL}}{\text{1.1066 g}} = \text{2052.3 mL} = \text{2.0523 L}$

5. Molar concentration

$\begin{array}{rcl}c & = & \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c & = & \dfrac{\text{4.666 mol}}{\text{2.0523 L}}\\\\ & = & \text{2.274 mol/L}\\\end{array}\\$

$\text{The molar concentration of the solution is} \boxed{\textbf{2.274 mol/L}}$

5 0

4 years ago

A 50.0 mL sample of 1.54×10−2 M NaSO4 is added to 50.0 mL of 1.28×10−2 Ca(NO3)2. What percentage of the Ca2+ remains unprecipita

Gwar [14]

The reaction would be as shown below;
Na2SO4 + Ca(NO3)2 = CaSO4 + 2 NaNO3
The moles of NaSO4 will be;
= 0.05 × 0.0154 = 0.00077 moles
While the number of moles of Ca(NO3)2
= 0.05 × 0.0128 = 0.00064 moles
The mole ratio of sodium sulfate and calcium nitrate is 1:1
Ca(NO3)2 is the limiting reactant, so ignoring the Ksp of CaSO4, zero percent of the Ca^2+ ions remain unprecipitated.

3 0

3 years ago

The variable that stays constant when using the combined gas law is​

The variable that stays constant when using the combined gas law is