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3 years ago

In the periodic table, the period number indicates

Chemistry

1 answer:

sergey [27]3 years ago

8 0

Answer: option B. The number of the outer most energy level for elements in that period

Explanation:

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What is the bond angle in a tetrahedral molecule?

levacccp [35]

109.5

tetrahedral shape:
number of electron pair = 4,
number of bonded pair = 4,
number of lone pair = 0.

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3 years ago

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0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati

erastova [34]

Answer:

$[Ag^{+}]=4.2\times 10^{-2}M$

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

$BaCrO_4 (s)\leftrightharpoons Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ba^{2+}][CrO_{4}^{2-}]$

$1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]$

$[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}$

Now,

$Ag_{2}CrO_4(s) \leftrightharpoons 2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)$

$Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]$

$1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})$

$[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}$

$[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M$

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

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3 years ago

How is solute concentration related to the solute-solvent interactions and the rate at which the solute dissolves?

shusha [124]

Answer:

Explanation:

solute is what gets dissolved in the solvent

ie: salt in water. salt is the salute and the more of it you add to the water (solvent) the more interactions will occur increasing rate

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3 years ago

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A.It is used to generate electricity

amid [387]

Answer:

Pretty sure the answer is B

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100 Points!

Bogdan [553]

Answer:

I think that's gonna be 96g

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3 years ago