Hey the answer is population hope this helps
You must react 5.3 g H_2 to produce 47 g H_2O.
<em>Step 1</em>. Calculate the <em>moles of H_2O</em>
Moles of H_2O = 47 g H_2O × (1 mol H_2O/18.02 g H_2O) =2.61 mol H_2O
<em>Step 2</em>. Calculate the <em>moles of H_2
</em>
Moles of H_2 = 2.61 mol H_2O × (2mol H_2/2 mol H_2O) = 2.61 mol H_2
<em>Step 3</em>. Calculate the <em>mass of H_2</em>
Mass of H_2 = 2.61 mol H_2 × (2.016 g H_2/1 mol H_2) = 5.3 g H_2
Answer:
NO2
Explanation:
Calculate moles of Nitrogen and oxygen (assume total mass is 100g as you only have percentages therefore there is 63.6g of N and 36.4g of O) This is the ratio that they are in but you need the ratio to be in whole numbers therefore divide each number of moles by 2.275 (the moles of oxygen) to calculate the empirical formula. Hope this helps!
Answer:
Valence Electrons
Explanation:
Valence electrons are the electrons in the outermost shell and can be used to form bonds.
