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salantis [7]
3 years ago
15

SO2+O2 SO3 how many moles of O2 needed to combust 100.0g of sulfur dioxide

Chemistry
1 answer:
Oksanka [162]3 years ago
6 0

2SO2 + O2 ------> 2SO3


1) M(SO2)= 32.0 + 2*16.0 = 64 g/mol


2) 100.0 g SO2 * 1 mol SO2/64 g SO2 = 1.5625 mol SO2


3) 2SO2 + O2 ------> 2SO3

2 mol 1 mol

1.5625 mol x mol


x= 1.5625/2=0.78125 ≈ 0.7813 mol O2


Answer: 0.7813 mol O2.

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If an object has a density of 0.00018 g/cm cubed, what density would it be if it had a mass of 10kg
Vladimir79 [104]

Answer:

Explanation:

first to get the density of some thing you have to devide the mass by the volume so 0.00018 (divided) by 10 kg and that gives you ur answer

3 0
3 years ago
What type of organic compound has the empirical formula CH2O and can serve as energy storage or the starting material for fats a
Luda [366]
Carbohydrates. CH2O is the most basic formula of simple sugars.Empirical formula is the lowest whole number ratio of atoms in a formula.For example glucose is C6H12O6 can be reduced by 6 to get CH2O. Simples sugars include glucose and fructose which can serve as sources of energy for fats and amino acids.
4 0
3 years ago
In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of the obj
olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0
3 years ago
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 13^oC=273+13=286K

T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

3 0
3 years ago
which idea did john dalton include in his atomic theory? a. all atoms are the same size. b. atoms of the same element are identi
lapo4ka [179]
It might be c, because he came up with the plum pudding model.  or it might be that atoms of the same element are identical, but that's not true cuz ions are different and isotopes are different.
5 0
4 years ago
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