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salantis [7]
3 years ago
15

SO2+O2 SO3 how many moles of O2 needed to combust 100.0g of sulfur dioxide

Chemistry
1 answer:
Oksanka [162]3 years ago
6 0

2SO2 + O2 ------> 2SO3


1) M(SO2)= 32.0 + 2*16.0 = 64 g/mol


2) 100.0 g SO2 * 1 mol SO2/64 g SO2 = 1.5625 mol SO2


3) 2SO2 + O2 ------> 2SO3

2 mol 1 mol

1.5625 mol x mol


x= 1.5625/2=0.78125 ≈ 0.7813 mol O2


Answer: 0.7813 mol O2.

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It is a molecule because hydrogen is an element.
An element is made up of molecules
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A sample of n2 effuses in 255 s. how long will the same size sample of cl2 take to effuse?
7nadin3 [17]
For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:

R₁/R₂ = √(M₂/M₁)

Let 1 be N₂ while 2 be Cl₂

255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s

<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>
4 0
3 years ago
When Brian first sorted out his thoughts, he figured this was the first day after the crash and what did he think would happen n
Leya [2.2K]

It should be noted that when Brian first sorted out his thoughts, the first thing that he thought would happen next is that he would probably be rescued that day.

It should be noted that in Chapter 5 of Hatchet, Brian wakes up in the forest and then, he realized that he was desperately thirsty.

When Brian first sorted out his thoughts, he figured this was the first day after the crash and that he would probably be rescued that day. He believed that he was going to wither up and die if he doesn't get anything that he'll drink.

Learn more about excerpts on:

brainly.com/question/21400963

7 0
2 years ago
Match the compounds as organic (O) or inorganic (I).
SashulF [63]
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7 0
2 years ago
Read 2 more answers
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
3 years ago
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