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sergij07 [2.7K]
2 years ago
14

The path of an object projected at a 45 degree angle with initial velocity of 80 feet per second is given by the −32 2 function

h(x) = (80)2 x + x where x is the horizontal distance traveled and h(x) is the height in feet. Use the TRACE feature of your calculator to determine the height of the object when it has traveled 100 feet away horizontally.
Physics
1 answer:
Masteriza [31]2 years ago
6 0

Answer:

<h2>50 feet</h2>

Explanation:

Given the the path of an object at a 45° with initial velocity of 80 feet per second modeled by the equation h(x) = (-\dfrac{32}{80^2} )x^2 + x where;

x is the horizontal distance traveled and h(x) is the height in feet, if x is given as 100 ft, the height of the object will be gotten by simply substituting x = 100 into the modeled function as shown;

h(x) = (-\dfrac{32}{80^2} )x^2 + x\\\\h(100) = (-\dfrac{32}{80^2} )100^2 + 100\\\\h(100) = (-0.005 )100^2 + 100\\\\h(100) = (-0.005 )10,000 + 100\\\\h(100) = -50 + 100\\\\h(100) =50 feet

<em>Hence height of the object when it has traveled 100 feet away horizontally is 50 feet.</em>

<em></em>

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The area is a hemisphere of radius

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(b) 5.9\cdot 10^{-7} W

In this case, the area of the reflection is

A=0.22 m^2

So, if we use the intensity of the wave that we found previously, we can calculate the power of the aircraft's reflection using the same formula:

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(c) 8.7\cdot 10^{-18} W/m^2

We said that the power of the waves reflected by the aircraft is

P=5.9\cdot 10^{-7} W

If we assume that the reflected waves also propagate over a hemisphere of radius

r=104 km=1.04\cdot 10^5 m

which has an area of

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Then the intensity of the reflected waves at the radar site will be

I=\frac{P}{A}=\frac{5.9\cdot 10^{-7} W}{6.8\cdot 10^{10} m^2}=8.7\cdot 10^{-18} W/m^2

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