Answer:

Explanation:
Given


Required
Determine the object's speed
Kinetic Energy is calculated as:

Make m the subject

Momentum is calculated as:

Make m the subject

So, we have:
and 
Equate both expressions: 

Multiply both sides by v


Make v the subject

Substitute
and 



Velocity of vw bug is given as
towards north
velocity of imphala is given as
towards south
now we need to find velocity of imphala relative to bug


so the speed is 101 mpH towards south so correct option is C
To measure the mass, you would use a balance. To measure the volume, you can use a variety of ounces, cups, pints, quarts, and gallons. Good luck!
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. The type of machine that a wire cutter pliers is classified is a simple machine. When we say simple machine, this is the type of machine that is considered basic wherein you need to apply force for it to function. Hope this helps.
Answer:
93 km/h
Explanation:
Given that a bus took 8 hours to travel 639 km. For the first 5 hours, it travelled at an average speed of 72 km/h
Let the first 5 hours journey distance = F
From the formula of speed,
Speed = distance/time
Substitute speed and time
72 = F/5
F = 72 × 5 = 360 km
The remaining distance will be:
639 - 360 = 279km
The remaining time will be:
8 - 5 = 3 hours
Speed = 279/3
Speed = 93 km/h
Therefore, the average speed for the remaining time of the journey is equal to 93 km/h