Viruses use the energy of the ______ cells to reproduce themselves

Two positive charges of 6.0 x 10^-6 C are separated by 0.50 m. Calculate the force of electrical attraction

SpyIntel [72]

Answer:

Force between two charges is given as 1.296 N

Explanation:

As we know that the two charges will attract or repel each other when they are placed near to each other

Here we know that electrostatic force is given as

$F = \frac{kq_1 q_2}{r^2}$

here we have

$q_1 = q_2 = 6 \times 10^{-6} C$

distance between two charges is given as

r = 0.50 m

so we have

$F = \frac{(9\times 10^9)(6 \times 10^{-6})^2}{0.50^2}$

$F = 1.296 N$

3 0

3 years ago

When the current through an electromagnet ceases, what generally happens to the magnetic field?

kati45 [8]

When the current flow ceases, the magnetic flow also decreases

3 0

2 years ago

A water dwelling slug like animal

rusak2 [61]

The answer you are looking for is a leech!

Hope this helps!

8 0

3 years ago

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A thin spherical shell with radius R1 = 4.00 cm is concentric with a larger thin spherical shell with radius R2 = 6.00 cm . Both

kakasveta [241]

Answer:

The right response will be "450 volts".

Explanation:

The given values are:

R1 = 4.00 cm

R2 = 6.00 cm

q1 = +6.00 nC

q2 = −9.00 nC

As we know,

The potential difference between the two shell's difference will be:

⇒ $\Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]$

$=K[\frac{q1}{R2}-\frac{q1}{R1} ]$

On substituting the values, we get

$=(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]$

Δ $=450 \ volts$

3 0

3 years ago

A shopper is pushing a cart down a grocery store aisle. Starting from rest, the shopper applies a constant force to the cart for

inysia [295]

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

A shopper is pushing a cart down a grocery store aisle. The movement of the cart is:

It starts from rest.
From t = 0 s to t = 4.0 s it is accelerated with a constant force.
From t = 4 s to t = 8.0 s it receives just enough force to balance the friction on the cart.
From t = 8 s to t = 12 s it is decelerated until it comes to rest.

All in all, at the initial time (t = 0 s), the velocity is 0 m/s (rest) and at the final time (t = 12 s) the velocity is 0 m/s as well (rest). The average acceleration in that period is:

$a = \frac{v_{12}-v__o}{t_{12}-t_0} = \frac{0m/m-0m/s}{12s-0s} = 0 m/s^{2}$

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

Learn more: brainly.com/question/16274121

3 0

2 years ago

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Viruses use the energy of the ______ cells to reproduce themselves​

Viruses use the energy of the ______ cells to reproduce themselves