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Shtirlitz [24]
4 years ago
5

Select the correct answer.

Physics
1 answer:
aksik [14]4 years ago
4 0
I don’t understand it I
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Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter
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We can solve the problem by using the first law of thermodynamics:

\Delta U= Q-W

where

\Delta U is the variation of internal energy of the system

Q is the heat added to the system

W is the work done by the system

In this problem, the variation of internal energy of the system is

\Delta U=U_f-U_i=134 J-87 J=47 J

While the heat added to the system is

Q=500 J

therefore, the work done by the system is

W=Q-\Delta U=500 J-47 J=453 J

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