Select the correct answer.

A long string is wrapped around a 6.6-cm-diameter cylinder, initially at rest, that is free to rotate on an axle. The string is

lys-0071 [83]

Answer:

$\omega_f=571.42\ rpm$

Explanation:

It is given that,

Diameter of cylinder, d = 6.6 cm

Radius of cylinder, r = 3.3 cm = 0.033 m

Acceleration of the string, $a=1.5\ m/s^2$

Displacement, d = 1.3 m

The angular acceleration is given by :

$\alpha =\dfrac{a}{r}$

$\alpha =\dfrac{1.5}{0.033}$

$\alpha =45.46\ rad/s^2$

The angular displacement is given by :

$\theta=\dfrac{d}{r}$

$\theta=\dfrac{1.3}{0.033}$

$\theta=39.39\ rad$

Using the third equation of rotational kinematics as :

$\omega_f^2-\omega_i^2=2\alpha \theta$

Here, $\omega_i=0$

$\omega_f=\sqrt{2\alpha \theta}$

$\omega_f=\sqrt{2\times 45.46\times 39.39}$

$\omega_f=59.84\ rad/s$

Since, 1 rad/s = 9.54 rpm

So,

$\omega_f=571.42\ rpm$

So, the angular speed of the cylinder is 571.42 rpm. Hence, this is the required solution.

5 0

4 years ago

HEY CAN ANYONE HELP ME OUT IN DIS RQ!!!!!!

shusha [124]

Answer:

40 laps

Explanation:

400/10=40

8 0

3 years ago

Analyze the effects on a passenger riding in a car traveling at

Mamont248 [21]

Without:

The passenger will get seriously injured
Colliding with the windshield at 50km/h
Could result in death

With safety:

The seatbelt holds tge passengers body back so they dont collide with anything
Their head is cushioned by the airbag
The passenger might get minor injuries but nothing serious will happen

5 0

3 years ago

An 80-kg astronaut becomes separated from his spaceship. He is 15.0 m away from it and at rest relative to it. In an effort to g

9966 [12]

The astronaut will take 300 seconds

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum of the astronaut+object system must be conserved.

Initially, they are both at rest, so their total momentum is zero:

$p=0$

After the astronaut throws the object, their total momentum is:

$p=MV+mv$

where:

M = 80 kg is the mass of the astronaut

V is the final velocity of the astronaut

m = 500 g = 0.5 kg is the mass of the object

v = 8.0 m/s is the velocity of the object

Since momentum is conserved, we can write

$0=MV+mv$

And solving for V,

$V=-\frac{mv}{M}=-\frac{(0.5)(8.0)}{80}=-0.05 m/s$

Which means that he starts moving at 0.05 m/s in the direction opposite to the object.

Now the astronaut needs to cover a distance of

d = 15.0 m

And his speed is

v = 0.05 m/s

Therefore, the time taken is

$t=\frac{d}{v}=\frac{15.0}{0.05}=300 s$

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

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#LearnwithBrainly

3 0

4 years ago

Which of the following is equivalent to Planks constant

Alinara [238K]

Answer:

6.62607004 x 10^(-34)m²kg/s

Explanation:

This is the constant that shows the value of energy of a photon in relation to it's frequency.

Please let me know if you want this explained further!

Thanks!

8 0

3 years ago