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mote1985 [20]
3 years ago
6

A level curve on a country road has a radius of 150 m. What is the maximum speed at which this curve can be safely negotiated on

a rainy day when the coefficient of friction between the tires on a car and the road is 0.40?
Physics
1 answer:
SSSSS [86.1K]3 years ago
8 0

The maximum speed of the car is 24.3 m/s

Explanation:

For a car moving along an unbanked turn, the frictional force provides the centripetal force required to keep the car in circular motion. Therefore, we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force while the term on the right is the centripetal force, and where

\mu=0.40 is the coefficient of friction between the tires and the road

m is the mass of the car

g=9.8 m/s^2 is the acceleration of gravity

v is the speed of the car

r = 150 m is the radius of the curve

Solving for v, we find the (maximum) speed at which the car can move along the turn:

v=\sqrt{\mu gr}=\sqrt{(0.40)(9.8)(150)}=24.3 m/s

For speed larger than this value, the frictional force is no longer enough to keep the car along the turn.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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How much force is required (in Newton’s) to accelerate a 4-kg skateboard, along with its 46-kg rider, at 3m/s2?
Soloha48 [4]

Answer:150N

Explanation:

Total mass=mass of skate board + mass of rider

Total mass(m)=46kg + 4kg

Total mass(m)=50kg

Acceleration(a)=3m/s^2

Force(f)=mass x acceleration

Force=50 x 3

Force=150N

5 0
3 years ago
Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also incr
Annette [7]

Answer:

P = 251,916.667 W

Cost = 2,267.25 cents

Explanation:

To solve this question we will use the Work Energy Theorem, which is

W = dP + dK\\

Where

dP = Change in Potential Energy

dK = Change in Kinetic Energy

Change in Potential Energy

P_{i} = mgh_{i}\\  P_{f} = mgh_{f}

Where

P_{i} = Initial Potential Energy

P_{f} = Final Potential Energy

m = Mass of System = 10,000 kg

g = Acceleration due to gravity = 9.81 m/s

h_{i} = Initial Height = 0

h_{f} = Final Height = 30 m

Inputting the values we get the answer for dP

dP = P_{f} - P_{i}\\dP= mgh_{f} - mgh_{i}\\ dP= 10000(9.81)(30) - 0\\ dP= 2943000

Change in Kinetic Energy

K_{i} = \frac{1}{2} mv_{i} ^2\\ K_{f} = \frac{1}{2} mv_{f} ^2

Where

K_{i} = Initial Kinetic Energy

K_{f} = Final Kinetic Energy

m = Mass of System = 10,000 kg

g = Acceleration due to gravity = 9.81 m/s

v_{i} = Initial Velocity = 0 m/2

v_{f} = Final Velocity = 4 m/s

Inputting the values we get the answer for dK

dK = K_{f} - K_{i}\\ dK = \frac{1}{2} mv_{f} ^2 - \frac{1}{2} mv_{i} ^2\\ dK = \frac{1}{2} (10000)(4)^2 - 0 \\ dK = 80000

Total Work

W = dP + dK\\

Inputting the values

W = 2943000 + 80000

W = 3,023,000

a) Finding the useful Power Output

P = \frac{W}{t}

Where

P = Power Output

W = Work Done = 3,023,000J

t = Time = 12s

Inputting the values

P = \frac{3,023,000}{12}\\ P = 251,916.667

P = 251,916.667 W

b) Finding the Total Cost

Cost = $0.0900 x P/1000

Cost = $0.0900 x (251,916.667/1000)

Cost = $22.67 or 2,267.25 cents

4 0
3 years ago
As a mouse sits on a desk, it has a gravitational force of 1x10^-9N pulling it towards the keyboard. If a different mouse with t
Nikitich [7]

Answer:

The new gravitational pull would be three times as strong as the first which would be 0.000000003 or 3 × 10^-9N.

Explanation:

Hope this helps. . . <3

8 0
3 years ago
Block A, with a mass of 4.0 kg, is moving with a speed of 3.0 m/s while block B, with a mass of 6.0 kg, is moving in the opposit
ElenaW [278]

Answer:

The momentum of the two-block system is 18 kg-m/s

Explanation:

It is given that,

Mass of block A, m_A=4\ kg  

Mass of block B, m_B=6\ kg  

Velocity of block A, v_A=3\ m/s  

Velocity of block B, v_B=-5\ m/s (it is moving in opposite direction)

We need to find the momentum of two block system. It is given by the product of mass and velocity for both blocks i.e.

p=m_Av_A+m_Bv_B

p=4\ kg\times 3\ m/s+6\ kg\times (-5\ m/s)

p = -18 kg-m/s

So, the momentum of two block system is 18 kg-m/s. Hence, this is the required solution.                                            

5 0
3 years ago
An object accelerates 3 m/s2 , when a force of 6 N acts on it. What is the object’s mass
telo118 [61]

Answer:

<h2>2 kg</h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{6}{3}  \\  = 2

We have the final answer as

<h3>2 kg</h3>

Hope this helps you

3 0
3 years ago
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