You have a lens whose focal length is 6.91 cm. You place an object on the axis of the lens at a distance of 11.1 cm from it. How
1 answer:
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A. the direction the object is moving in will not change.
B. the acceleration of the object will be 0 m/s2
Explanation:
We can answer this problem by using Newton's second law of motion:
where
is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, all the forces acting on the object are balanced, therefore the net force is zero:
which means that also the acceleration is zero:
Acceleration is equal to the rate of change of velocity: therefore, zero acceleration means that the velocity of the object does not change. We can now analyze the given statements:
A. the direction the object is moving in will not change. --> TRUE, because the velocity is not changing.
B. the acceleration of the object will be 0 m/s2 --> TRUE, as we stated above
c. the object will not be in motion. --> FALSE: we just know that its velocity is constant, but it can be different from zero
D. the velocity of the object will be 0 m/s. --> FALSE, for the same reason stated in C
Learn more about Newton's second law of motion:
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Answer:
a) 20 seconds
b) No.
Explanation:
t = Time taken for jet to stop
u = Initial velocity = 100 m/s (given in the question)
v = Final velocity = 0 (because the jet will stop at the end)
s = Displacement of the jet (Distance between the moment the jet touches the ground to the point the point it stops)
a = Acceleration = -5.00 m/s² (slowing down, so it is negative)
a) Equation of motion
The time required for the plane to slow down from the moment it touches the ground is 20 seconds.
The distance it requires for the jet to stop is 1000 m so in a small tropical island airport where the runway is 0.800 km long the plane would not be able to land. The runway needs to be atleast 1000 m long here the runway on the island is 1000-800 = 200 m short.