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Vedmedyk [2.9K]
3 years ago
10

You have a lens whose focal length is 6.91 cm. You place an object on the axis of the lens at a distance of 11.1 cm from it. How

far is the object\'s image from the lens?
Physics
1 answer:
stellarik [79]3 years ago
7 0

Answer:

4.2591 cm

Explanation:

We have given focal length of the lens f=6.91 cm

Object distance u =11.1 cm

We have to find the image distance that is v

For the lens we know that \frac{1}{f}=\frac{1}{v}-\frac{1}{u}

So \frac{1}{6.91}=\frac{1}{v}-\frac{1}{11.1}

0.1447=\frac{1}{v}-0.09

\frac{1}{v}=0.2347

v=4.2591cm

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A 950-kg car strikes a huge spring at a speed of 22m/s (fig. 11-54), compressing the spring 5.0m. (a) what is the spring stiffne
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(a) The spring stiffness constant of the spring is 18,392 N/m.

(b) The time the car was in contact with the spring before it bounces off in the opposite direction is 0.23 s.

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<h3>Force exerted on the spring</h3>

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<h3>Time of impact</h3>

F = mv/t

t = mv/F

t = (950 x 22)/(91960)

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Learn more about spring constant here: brainly.com/question/1968517

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