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2 years ago

How has access to the source code of proprietary software?

2 answers:

6 0

Proprietary software is the software that is owned by an individual or the company that developed it.
<span><span>Source code is the basic component of a computer program and it </span>is the only component where a programmer can read and modify a computer program.</span>
<span>The source code for proprietary <span>software is closed. Only the programmers who have made the software have access to the source code. </span></span>

dezoksy [38]2 years ago

3 0

Answer:

Explanation:

It's a software publisher

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A top-fuel dragster starts from rest and has a constant acceleration of 42.0 m/s2. What are (a) the final velocity of the dragst

disa [49]

Answer:

a) Final velocity of the dragster at the end of 1.8 s = 75.6 m/s

b) Final velocity of the dragster at the end of 3.6 s = 151.2 m/s

c) The displacement of the dragster at the end of 1.8 s = 68.04 m

d) The displacement of the dragster at the end of 3.6 s = 272.16 m

Explanation:

a) We have equation of motion v = u + at

Initial velocity, u = 0 m/s

Acceleration , a = 42 m/s²

Time = 1.8 s

Substituting

v = u + at

v = 0 + 42 x 1.8 = 75.6 m/s

Final velocity of the dragster at the end of 1.8 s = 75.6 m/s

b) We have equation of motion v = u + at

Initial velocity, u = 0 m/s

Acceleration , a = 42 m/s²

Time = 3.6 s

Substituting

v = u + at

v = 0 + 42 x 3.6 = 75.6 m/s

Final velocity of the dragster at the end of 3.6 s = 151.2 m/s

c) We have equation of motion s= ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration , a = 42 m/s²

Time = 1.8 s

Substituting

s= ut + 0.5 at²

s = 0 x 1.8 + 0.5 x 42 x 1.8²

s = 68.04 m

The displacement of the dragster at the end of 1.8 s = 68.04 m

d) We have equation of motion s= ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration , a = 42 m/s²

Time = 3.6 s

Substituting

s= ut + 0.5 at²

s = 0 x 3.6 + 0.5 x 42 x 3.6²

s = 272.16 m

The displacement of the dragster at the end of 3.6 s = 272.16 m

3 0

2 years ago

Two forces act on an object. The first force has a magnitude of 15.0 N and is oriented 78.0 ° counterclockwise from the + x ‑axi

bezimeni [28]

Answer:

Explanation:

fffkfkfk

4 0

3 years ago

A solid, uniform sphere with a mass of 2.5 kg rolls without slipping down an incline plane starting from rest at a vertical heig

kolezko [41]

Answer:

1/2 m v^2 + 1/2 I ω^2 = m g h conservation of energy

I = 2/5 m R^2 inertia of solid sphere

1/2 m v^2 + 1/5 m ω^2 R^2 = m g h

1/2 v^2 + 1/5 v^2 = g h

v^2 = 10 g h / 7 = 1.43 * 9.80 * 19 m^2/s^2 = 266 m^2/s^2

v = 16.3 m/s

v = R ω

ω = 16.3 / .6 = 27.2 / sec

8 0

2 years ago

Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.3 m long hollow tube in the cr

yarga [219]

Answer:

67.31 Hz, 201.92 Hz, 336.54 Hz

Explanation:

Resonance also known as standing wave occur when a uniform tube is closed at one end and open at the other end.

For a resonance wave in a tube with length b, wavelength λ of resonance wave is 4b because a quarter wave is formed in the tube, that is,

λ = 4b.

When the speed of sound is c, the frequency of sound, f, is

f = c /λ,

and therefore,

f = c / ( 4b ).

From the question,

When c = 350 m/s and b = 1.3 m,

using the formula

fn = c / ( 4b ) × n (n = 1, 3, 5, ...).

The first three resonant frequencies are;

First resonance frequency is

f = 350 / (4*1.3) * 1 = 67.31 Hz

Second resonance frequency is

f = 350 / (4*1.3) * 3 = 201.92 Hz

Third resonance frequency is

f = 350 / (4*1.3) * 5 = 336.54 Hz

5 0

3 years ago

A vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, as shown in the figure. While

kvasek [131]

For a vertical spring launcher is attached to the top of a block and a ball is placed in the launcher, the position of the ball will be behind the box

<h3>What will be the position of the ball relative to the spring launcher?</h3>

Generally, the equation for the conservation of momentum principle is mathematically given as

(M+m) V1 = M*V2

Therefore, with the ball moving forward we have that; the ball at top it wii be behind the box,