Answer:
V = 331.13 mL of 50 by mass NO3 solution
Explanation:
∴ δ sln = 2.00 g/mL
∴ %m HNO3 = 50% = ( mass HNO3 / mass sln ) × 100
∴ V required sln = 500 mL
∴ δ HNO3 = 1.51 g/mL.......from literature
⇒ V sln = mass sln / δ sln = 500 mL
⇒ mass sln = (500 mL )×( 2 g/mL ) = 1000 g sln
⇒ mass HNO3 = ( 0.5 )×(1000 g) = 500 g HNO3
⇒ V HNO3 = ( 500 g HNO3 )×(ml HNO3/1.51 g ) = 331.13 mL
Answer:
The amount of heat is 84.4894kJ
Explanation:
Given data:
mass of octane=148g
The moles of octane is:

The melting point is=-56.82°C
ΔHfus=20.73kJ/mol
The heat of fusion is:

The heat to bring the octane to a temperature of 117.8°C is:

The total heat in the process is:
Qtotal=Qfus+Q₂=26.8578+57.6316=84.4894kJ
H + N = NH3
Hydrogen plus nitrogen is ammonia. This is covalent bond.
Answer : Oxidizing agent is
and Reducing agent is 
Explanation :
The given unbalanced redox reaction is,

In acidic medium, the balanced redox reaction is,

Oxidizing agent : Oxidizing agents are those agent which oxidizes other substance and itself get reduced.
Reducing agent : Reducing agents are those agent which reduces other substance and itself get oxidized.
In this redox reaction,
is an oxidizing agent and
is a reducing agent.
The redox reaction is also shown below.