Answer:
½O 2 + 2e - + H 2O → 2OH.
Explanation:
Redox reactions - Higher
In terms of electrons:
oxidation is loss of electrons
reduction is gain of electrons
Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:
iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-
oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-
iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-
P1v1/t1 = p2t2/t2
p is constant
v1=600, t1 =20c=293K
v2=?, t2=60c=333K
temperature must be in Kelvin
do the math
<h2>
Answer:</h2>
ZINC
<h2>
Explanation:</h2>
<em>To identify the element based on the informartion given, we have to find the molar mass since this mass is unique to each element.</em>
Molar mass = mass ÷ moles
<em>We already know the mass based on the question, as such we now need to find the # of moles.</em>
Since 1 mole contains 6.02214 × 10²³ atoms
then let x moles contain 4.19 × 10²³ atoms <em>(given in the question)</em>
<em> </em><em> </em> ⇒ x = (4.19 × 10²³ atoms × 1 mol) ÷ 6.02214 × 10²³ atoms
x = 0.69577 mol
<em>Now that we have the moles we can substitute it into the molar mass equation and solve for the molar mass.</em>
⇒ molar mass = 45.6 g ÷ 0.69577 mol
⇒ molar mass ≈ 65.54 g/mol
This molar mass is closest to that of ZINC.
It 1
cause yea it is im doing it in class and the answers is 1
A) NaCl = 58.44 g/mol
number of moles : 2.14 / 58.44 = 0.0366 moles
V = n / M => 0.0366 / 0.270 = 0.1355 L
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b) C2H6<span>O = 46.06 g/mol
</span>number of moles : 4.30 / 46.06 = 0.0933 moles
<span>V = n / M => 0.0933 / 1.50 = 0.0622 L
</span>___________________________________________
c) CH3COOH = 60.0 g/mol
number of moles : 0.85 / 60.0= 0.0141 moles
V = n / M => <span> 0.0141 </span>/ 0.30 = 0.047 L
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hope this helps!
