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NNADVOKAT [17]
3 years ago
10

PLEASE HELP!!

Physics
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

D

Explanation:

Michael Faraday is probably best known for his discovery of electromagnetic induction, his contributions to electrical engineering and electrochemistry or due to the fact that he was responsible for introducing the concept of field in physics to describe electromagnetic interaction.

Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.

Electrical engineering is an engineering discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism.

Electrochemistry is the branch of physical chemistry that studies the relationship between electricity, as a measurable and quantitative phenomenon, and identifiable chemical change, with either electricity considered an outcome of a particular chemical change or vice versa.

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When a particular wire is vibrating with a frequency of 4.00 Hz, a transverse wave of wavelength 60.0 cm is produced. Determine
astraxan [27]

Answer : The speed of waves along the wire is, 1.2 m/s

Explanation :

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency = 4.00Hz=4.00s^{-1}

\lambda = wavelength = 30.0cm=0.3m

c = speed of wave = ?

Now put all the given value in the above formula, we get the speed of waves along the wire.

4.00s^{-1}=\frac{c}{0.3m}

c=1.2m/s

Thus, the speed of waves along the wire is, 1.2 m/s

6 0
3 years ago
A uniform thin rod of mass ????=3.41 kg pivots about an axis through its center and perpendicular to its length. Two small bodie
vivado [14]

Answer:

The length of the rod for the condition on the question to be met is L  =  1.5077 \ m

Explanation:

The  Diagram for this  question is  gotten from the first uploaded image  

From the question we are told that

          The mass of the rod is M  =  3.41 \ kg

           The mass of each small bodies is  m =  0.249 \ kg

           The moment of inertia of the three-body system with respect to the described axis is   I  =  0.929 \ kg \cdot  m^2

             The length of the rod is  L  

     Generally the moment of inertia of this three-body system with respect to the described axis can be mathematically represented as

        I =  I_r + 2 I_m

Where  I_r is the moment of inertia of the rod about the describe axis which is mathematically represented as  

        I_r  =  \frac{ML^2 }{12}

And   I_m the  moment of inertia of the two small bodies which (from the diagram can be assumed as two small spheres) can be mathematically represented  as

           I_m  =   m * [\frac{L} {2} ]^2 =  m*  \frac{L^2}{4}

Thus  2 *  I_m  =  2 *  m  \frac{L^2}{4}  = m  *  \frac{L^2}{2}

Hence

       I  =  M  *   \frac{L^2}{12}  +  m  * \frac{L^2}{2}

=>   I  =    [\frac{M}{12}  + \frac{m}{2}] L^2

substituting vales  we have  

        0.929   =    [\frac{3.41}{12}  + \frac{0.249}{2}] L^2

       L  =  \sqrt{\frac{0.929}{0.40867} }

      L  =  1.5077 \ m

     

6 0
3 years ago
. What is the kinetic energy of a 10 kg car that is moving 4 m/s?
Darya [45]

Answer:i belive the answer is E = 1/2 mv^2

hope this helps plz mark me as braliest

8 0
3 years ago
What is the speed of the object in the graph? Explain​
Nikolay [14]

Answer:

0.8m per second

Explanation:

we measure speed as distance over time

distance=8m

time=10s

therefore speed = 8/10

=0.8m per second

5 0
3 years ago
Read 2 more answers
The double inclined plane supports two blocks A and B, each having a weight of 10 lb. If the coefficient of kinetic friction bet
Vladimir79 [104]

Answer:

Explanation:

Left block is on surface with higher inclination so it will go down . If T be tension

For motion of block A ,

net force = mgsin60 - (T + mg cos 60 x μ ) , μ is coefficient of friction .

ma =  mgsin60 - T -  mg cos 60 x .1

10a = 277.13  - T - 16

= 261.13 - T

T = 261.13 - 10a

For motion of block B

T - mg sin30 - mgcos30 x μ = ma

T- 160 - 27.71 = 10 a

261.13 - 10a - 160 - 27.71 = 10a

73.42 = 20a

a = 3.67 ft / s²

common acceleration = 3.67 ft / s²

8 0
4 years ago
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