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NNADVOKAT [17]
3 years ago
10

PLEASE HELP!!

Physics
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

D

Explanation:

Michael Faraday is probably best known for his discovery of electromagnetic induction, his contributions to electrical engineering and electrochemistry or due to the fact that he was responsible for introducing the concept of field in physics to describe electromagnetic interaction.

Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.

Electrical engineering is an engineering discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism.

Electrochemistry is the branch of physical chemistry that studies the relationship between electricity, as a measurable and quantitative phenomenon, and identifiable chemical change, with either electricity considered an outcome of a particular chemical change or vice versa.

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The answer is c capacitance
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Which statement is true ?
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A solid wood door 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 40.0 kg. Initially open and at re
xxTIMURxx [149]

Answer:

The final angular speed is 0.223 rad/s

Explanation:

By the conservation of angular moment:

ΔL=0

L₁=L₂

L₁ is the initial angular moment

L₂ is the final angular moment

L₁ is given by:

L_1=L_{door} + L_{mud}

As the door is at rest its angular moment is zero and the angular moment of mud can be considered as a point object, then:

L_1= L_{mud}= mvr

where

r is the distance from the support point to the axis of rotation (the mud hits at the center of the door; r=0.5 m)

v is the speed

m is the mass of the mud

L₂ is given by:

L_2= (I_{door} + I_{mud}) \omega_f

ωf is the final angular speed

The moment of inertia of the door can be considered as a rectangular plate:

I_{door}=\frac{1}{3}MW^2

M is the mass of the door

W is the width of the door

The moment of inertia of the mud is:

I_{mud}=mr^2

Hence,

L_1=L_2\\mvr= (I_{door} + I_{mud}) \omega_f\\\omega_f=\frac{mvr}{I_{door} + I_{mud}} \\\omega_f=\frac{mvr}{I_{door} + I_{mud}}

\omega_f=\frac{0.5kg \times 12m/s \times 0.5m}{\frac{1}{3}40kg(1m)^2+0.5kg \times (0.5m)^2}

\omega_f=0.223 \frac{rad}{s}

6 0
4 years ago
A square coil, enclosing an area with sides 3.2 cm long, is wrapped with 2,720 turns of wire. A uniform magnetic field perpendic
marishachu [46]

Answer

\epsilon = -0.74\ V

Explanation:

given,                          

Side of square coil = 3.2 cm            

Number of turns = 2720                  

magnetic field in the coil increases to = 0.45 T

time interval = 1.7 s                  

average induced voltage in the coil = ?

length = 0.032 m                      

Area = 0.032² = 0.001024 m²

induced voltage                  

\epsilon = -NA \dfrac{dB}{dt}

\epsilon = -2720 \times 0.001024 \times \dfrac{0.45}{1.7}

\epsilon = -0.74\ V                          

The average voltage induced in the coil is equal to \epsilon = -0.74\ V                                              

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