Answer:
Increase the amplitude
Explanation:
The energy conveyed by a wave is directly proportional to the square of its amplitude. Thus; E ∝ A²
This means that increasing the amplitude will lead to an increase in the energy.
Now, the amplitude of a wave is the height of a wave from it's highest point known as the peak, to the lowest point on the wave known as the trough whereas wavelength refers to the length of a wave from one peak to the next.
This means that increasing the amplitude has no effect on the wavelength.
Answer:
Explanation:
It is given that,
Electric field due to the spark,
Dimensions of the parallel-plate capacitor is 5.1 cm × 5.1 cm.
The area of the parallel plate,
The electric field due to the parallel plate capacitor is given by :
Let n is the number of electrons that must transferred from one plate to the other to create a spark between the plates. It can be calculated as :
So, the number of electrons must be transferred from one plate to the other is . Hence, this is the required solution.
If you stay on the same planet and drop a lot of objects one at a time,
it turns out that every object you drop falls from your hand to the ground
with the same acceleration, and hits the ground with the same speed,
no matter whether the object is light, heavy, or anything in between.
That particular value of acceleration is the "acceleration due to gravity".
On Earth, it's 9.81 meters per second². On the moon, it's 1.62 meters
per second². On Jupiter, it's 25.89 meters per second².
Why we don't generally notice it: The previous description is true if the
ONLY force on the object is the force of gravity. If it has to fall through
<u>air</u> on the way down, then the air can have a great effect on it. Many
museums have an exhibit where they drop things in a long tube with
all the air removed from it, and there you can see some pretty weird
stuff ... like a bowling ball, a rock, a sheet of paper, and a feather, all
falling together, with nothing fluttering.
<u>Why</u> everything falls with the same acceleration ? That's a separate question.
<u>Answer:</u>
<em>The required radius of its motion is .</em>
<u>Explanation:</u>
The formula for calculating the required radius of its motion is given by
Where <em>m= mass </em>
<em>V= moving velocity
</em>
<em>F=frictional force
</em>
<em>r = radius of its motion
</em>
Then the required radius of its motion is given by
<u>Given that
</u>
<em>mas =0.0818 kg
</em>
<em>Frictional force= 0.108 N
</em>
<em>Moving with Velocity of = 0.333 m/s
</em>
<em>radius of its motion = </em>
<em>Hence the required radius of its motion is r = </em>