330 g of water at 55°c are poured into an 855 g aluminum container with an initial temperature of 10°
1 answer:
The final temperature of the system is 32.5°
we know, H = mcT
where, H = Heat content of the body
m = Mass,
c = Specific heat
T = Change in temperature
According to to the Principle of Calorimetry
The net heat remains constant i.e.
⇒ the heat given by water = heat accepted by the aluminum container.
⇒ 330 x 1 x (45 - T) = 855 x
x (T - 10)
⇒ 14,850 - 330T = 183.21T - 1832
⇒ - 513.21 T = - 16682
or T = 32.5°
we know, H = mcT
where, H = Heat content of the body
m = Mass,
c = Specific heat
T = Change in temperature
According to to the Principle of Calorimetry
The net heat remains constant i.e.
⇒ the heat given by water = heat accepted by the aluminum container.
⇒ 330 x 1 x (45 - T) = 855 x
⇒ 14,850 - 330T = 183.21T - 1832
⇒ - 513.21 T = - 16682
or T = 32.5°
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Answer:
Explanation:
According to the given information (and figure attached), the block with mass has the following forces acting on it:
In the X component:
(1)
Where:
is the applied force directed
above the horizontal
(2) is the force of static friction (which is equal to the coefficient of static friction
and the Normal force
In the Y component:
(3)
Where is the weight (the force of gravity) which is proportional to the multiplication of the mass
and gravity
Let’s begin by combining (1) and (2):
(4)
Isolating from (3):
(5)
Substituting (5) in (4):
(6)
Isolating :
(7)
Finally:
(8) This is the necessary force to overcome static friction and move the block
We can prove it by finding and verifying it is less than
:
Substituting (8) in (1):
(9)
(10) This is the static friction force
As we can see
