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svet-max [94.6K]
3 years ago
15

330 g of water at 55°c are poured into an 855 g aluminum container with an initial temperature of 10°

Physics
1 answer:
Olenka [21]3 years ago
3 0
The final temperature of the system is 32.5°
we know,  H = mcT 
where, H = Heat content of the body 
m = Mass,
c = Specific heat
T = Change in temperature
According to to the Principle of Calorimetry 

The net heat remains constant i.e. 
⇒ the heat given by water = heat accepted by the aluminum container.
⇒ 330 x 1 x (45 - T) = 855 x \frac{900}{4200} x (T - 10) 

⇒ 14,850 - 330T = 183.21T  - 1832 

⇒ - 513.21 T = - 16682

or T = 32.5°
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A. Their particles are free to move away from each other.

Explanation:

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A hydraulic lift raises a 4000 kg automobile when a 500N force is applied to the smaller piston. If the smaller piston has an ar
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Answer:

The cross-sectional area of the larger piston is 800 cm².

Explanation:

Given;

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force applied on the small piston, F₁ = 500 N

area of the smaller piston, A₁ = 10 cm²

load lifted by the larger piston, F₂ = 4000 x 10 = 40,000 N

Pressure experienced by each piston is given as;

\frac{F_1}{A_1} = \frac{F_2}{A_2}

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A₂ is the cross-sectional area of the larger piston

\frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\A_2 = \frac{F_2A_1}{F_1} \\\\A_2 = \frac{40,000 \ \times\ 10}{500} \\\\A_2=800 \ cm^2

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3 years ago
What happens to heat energy after an object is cooled down lolololol asking for my bff
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A charge per unit length given by l(x) = bx, where b = 12 nc/m2, is distributed along the x axis from x = +9.0 cm to x = +16 cm.
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4 0
3 years ago
How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​
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Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

 Mathematically;

        Power  = \frac{work done}{time}  

   Time  = \frac{work done}{power}  

 Work done  = weight x height

 convert mass to kg;

     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

          1000mm = 1m

          6.34 x 10⁴mm gives 63.4m

  Work done  = 14.7 x 9.8 x 63.4 = 9133.4J

  Time taken = \frac{9133.4}{2190}   = 4.2s

6 0
3 years ago
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