Answer:
180.28 km/h
Explanation:
Let north and south represent the positive and negative y axis and east and west represent the positive and negative x axis.
Given;
Velocity of wind vx= 100 km/s
Velocity of aircraft in still air vy = 150 km/s
The resultant velocity Vr is;
Vr = √(vx^2 + vy^2)
Vr = √(100^2 + 150^2)
Vr = 180.2775637731 km/h
Vr = 180.28 km/h
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Answer:
1. -8.20 m/s²
2. 73.4 m
3. 19.4 m
Explanation:
1. Apply Newton's second law to the car in the y direction.
∑F = ma
N − mg = 0
N = mg
Apply Newton's second law to the car in the x direction.
∑F = ma
-F = ma
-Nμ = ma
-mgμ = ma
a = -gμ
Given μ = 0.837:
a = -(9.8 m/s²) (0.837)
a = -8.20 m/s²
2. Given:
v₀ = 34.7 m/s
v = 0 m/s
a = -8.20 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (34.7 m/s)² + 2 (-8.20 m/s²) Δx
Δx = 73.4 m
3. Since your braking distance is the same as the car in front of you, the minimum safe following distance is the distance you travel during your reaction time.
d = v₀t
d = (34.7 m/s) (0.56 s)
d = 19.4 m
