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kodGreya [7K]
3 years ago
10

Newton’s second law: Force equals mass times acceleration (__=___).

Physics
1 answer:
DIA [1.3K]3 years ago
7 0
F n = ma / unbalanced force - In the direction of the force.
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A man walks 600 m [E47°N], then 500 m [N38°W], then 300 m [W29°S], and finally 400 m [S13°E]. Find his resultant displacement.
Archy [21]

The horizontal component of an angular distance can be calculated by multiplying the distance with the cosine of the angle, Dx = D * cos θ

While the vertical component is calculated by multiplying the distance with the sine of the angle, Dy = D * sin θ

The resultant displacement can then be obtained using the formula for hypotenuse and summations of each component:

R^2 = (summation of Dx)^2 + (summation of Dy)^2

summation of Dx = 600 * cos47 + 500 * cos128 + 300 * cos209 + 400 * cos(-77) = -71.0372

summation of Dy = 600 * sin47 + 500 * sin128 + 300 * sin209 + 400 * sin(-77) = 297.6267

<span>                        Note: you have to draw the lines to correctly determine the angles</span>

R^2 = (-71.0372)^2 + 297.6267^2

R = 306 m

The resultant angle is:

tan θ = Dy / Dx

θ = tan^-1 (297.6267 / -71.0372)

θ = 103˚ = [N 13˚ W]

Therefore displacement is 306 m <span>[N 13˚ W].</span>

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4 years ago
Please help with these i dont know how to do them
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<em><u>2</u></em><em><u>0</u></em><em><u>.</u></em><em><u>0</u></em><em><u>M</u></em><em><u>/</u></em><em><u>S</u></em><em><u>. </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>HORIZONTAL</u></em><em><u> </u></em><em><u>VELOCITY</u></em><em><u> </u></em><em><u>OF</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>BALL</u></em><em><u> </u></em><em><u>JUST</u></em><em><u> </u></em><em><u>BEFORE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>REA</u></em><em><u>CHES</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>GROUND</u></em>

<em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>SECONDS</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>APPROXIMATE</u></em><em><u> </u></em><em><u>TOTAL</u></em><em><u> </u></em><em><u>TIME</u></em><em><u> </u></em><em><u>REQUIRED</u></em><em><u> </u></em><em><u>FOR</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>BALL</u></em>

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At the instant a ball is thrown horizontally with a large force, an identical ball is dropped from the same height. which ball h
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GalinKa [24]

Answer:

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Explanation:

It would be diffrent if on a downward slope but assuming your going straight it would be the smallest student.

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