Answer: 117 kPa
Explanation:
For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa
For the liquid at depth 9m, the gauge pressure is equal to= P₂
Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.
So, For finding gauge pressure we have formula P= ρ * g * h
Also gravity also remains same for both liquids
So taking ratio of their respective pressures we have
= 
So
= 
Or P₂= 39 * 3 = 117 kPa
Answer:
w= p∆v 50000 ( 0.55-0.40) and calculate and you get it
Answer:
7.9m/s
Explanation:
We are given that
Mass of wagon=40 kg

Tension=
Initial velocity of wagon=
Displacement=s=80 m
Net force applied on wagon=
By using 

We know that

Using the formula


Answer:
C.) 2H2O to 2H2+ O2 is the equation which represents a decomposition reaction.
41.2 = h-1/2g(t-1)^2
<span> {-h = -1/2gt^2-1/2g+g*t-41.2
</span><span> {h = 1/2gt^2
</span><span> summing them up
</span><span> 0 = -1/2g+g*t-41.2
</span><span> 41.2 +4.9 = g*t
</span><span> t = 46.1/9.8 = 4.70 sec
</span><span> h = 1/2gt^2 =4.9*(4.70^2) = 108.241 m </span>