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kodGreya [7K]
3 years ago
10

Newton’s second law: Force equals mass times acceleration (__=___).

Physics
1 answer:
DIA [1.3K]3 years ago
7 0
F n = ma / unbalanced force - In the direction of the force.
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Consider an embedded system which uses a battery with a 17.15-Amp-Hour capacity. What is the maximum average current draw (in mi
Marianna [84]

Answer:

<em>85.12 μAmp</em>

<em></em>

Explanation:

The battery power output = 17.15 Amp-hr

If the battery is to last 23 years, we have to calculate how many hours there are in 23 years

in one year there are 24 hours x 365 day = 8760 hrs

in 23 years there are 23 x 8760 = 201480 hours

maximum current to be drawn from the battery = (17.15 Amp-hr) ÷ (201480 hours) = 85.12 x 10^-6 Amp = <em>85.12 μA</em>

7 0
2 years ago
What is the uncertainty of the position of the bacterium? express your answer with the appropriate units?
lbvjy [14]
For two un-related quantities, the Heisenberg uncertainty equations holds: the prduct of the two uncertainty quantities is greater than \hbar/2
Example of unrelated quantities are position and momentum, energy and time. 
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\Delta x*\Delta p  \ \textgreater \ \hbar/2
Knowing the speed of the bacteria the uncertainty in its position is
\Delta x \ \textgreater \ \hbar/(2 \Delta p) =\hbar/(2mv)
4 0
3 years ago
This is my exam question be serious
elena-s [515]

Answer:

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6 0
3 years ago
State Schrodinger equation.​
Elenna [48]

Hi!Schrodinger equation is written as HΨ = EΨ, where h is said to be a Hamiltonian operator.

3 0
2 years ago
A 4.10 g bullet moving at 837 m/s strikes a 820 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
atroni [7]

Answer:

(a) 1.85 m/s

(b) 4.1 m/s

Explanation:

Data

  • bullet mass, Mb = 4.10 g
  • initial bullet velocity, Vbi = 837 m/s
  • wooden block mass, Mw = 820 g
  • initial wooden block  velocity, Vwi = 0 m/s
  • final bullet velocity, Vbf = 467 m/s

(a) From the conservation of momentum:

Mb*Vbi + Mw*Vwi = Mb*Vbf + Mw*Vwf

Mb*(Vbi - Vbf)/Mw = Vwf

4.1*(837 - 467)/820 = Vwf

Vwf = 1.85 m/s

(b) The speed of the center of mass speed is calculated as follows:

V = Mb/(Mb + Mw) * Vbi

V = 4.1/(4.1 + 820) * 837

V = 4.1 m/s

6 0
3 years ago
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