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Kruka [31]
3 years ago
11

GIVING BRAINLY !!!!!! Calculate the molar mass of MgBr2. “SHOW” Your work!

Chemistry
1 answer:
Dovator [93]3 years ago
8 0

Answer:

184.113 g/mol

Explanation:  The atomic mass of Mg is 24.3 amu. The atomic mass of bromine is 79.9. Therefore, the formula weight of MgBr2 equals 24.3 amu + (2 × 79.9 amu), or 184.1 amu. Because a substance's molar mass has the same numerical value as its formula weight, the molar mass of MgBr2 equals 184.1 g/mol.

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trapecia [35]
<h2>Answer:</h2>
  • Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s).

<u>Moles Cu present</u> = 100g Cu x 1 mol Cu/63.55g

= 1.574moles Cu

<u>Mass of Ag produced</u> = 1.574mol Cu x 2mol Ag / 1mol Cu x 107.9g Ag/mol Ag

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6 0
3 years ago
Use the periodic table to determine which of the
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B , C

Explanation :

[ Correct on Ed 2020 ]

3 0
4 years ago
A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori
Nitella [24]

Answer : The specific heat of metal is 0.481J/g^oC.

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of metal = 129.00 g

m_2 = mass of water = 45.00 g

T_f = final temperature = 39.6^oC

T_1 = initial temperature of metal = 97.8^oC

T_2 = initial temperature of water = 20.4^oC

Now put all the given values in the above formula, we get

129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC

c_1=0.481J/g^oC

Therefore, the specific heat of metal is 0.481J/g^oC.

4 0
4 years ago
Do liquids expand when they freeze
Oksana_A [137]

Answer:

most liquids do expand when they freeze

Explanation:

water is actually one that expands and there are probably many more too

i hope this helps you

8 0
3 years ago
Given the reaction:
olchik [2.2K]

Answer:

Option C. 200mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2NaOH + H2SO4 –> Na2SO4 + 2H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 2

The following data were obtained from the question:

Molarity of the base (Mb) = 1M

Volume of the base (Vb) =..?

Molarity of the acid (Ma) = 1M

Volume of the acid (Va) = 100mL

The volume of the base needed can be obtained as follow:

MaVa/MbVb = nA/nB

1 x 100 /1 xVb = 1/2

Cross multiply to express in linear form

Vb = 1 x 100 x 2

Vb = 200mL

Therefore, the volume of the base needed for the reaction is 200mL

3 0
3 years ago
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