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KiRa [710]
3 years ago
8

10Al + 6NH4ClO4 → 4Al 2O3 + 2AlCl 3 + 12H2O + 3N2

Chemistry
1 answer:
Zolol [24]3 years ago
4 0
1 Aluminium is oxidised Al - 3e = Al⁺³

2 Chlorine is reduced  Cl⁺⁷ + 8e = Cl⁻¹

3 Nitrogen is oxidised 2N⁻³ - 6e = N₂

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Which statement describes what is gained or lost during radioactive decay?
Karolina [17]

Answer:

The answer is

Atoms gain other atoms

Hope this helps you

3 0
3 years ago
Due to radioactive decay over many millions of years, it is possible for the element uranium to decay in
ruslelena [56]

The uranium within these items is radioactive and should be treated with care. Uranium's most stable isotope, uranium-238, has a half-life of about 4,468,000,000 years. It decays into thorium-234 through alpha decay or decays through spontaneous fission.

3 0
3 years ago
For many years chloroform (CHCl3) was used as an inhalation anesthetic in spite of the fact that it is also a toxic substance th
Debora [2.8K]

Hey there!:

Molar mass:

CHCl3 = ( 12.01 * 1 )+ (1.008 * 1 ) + ( 35.45 * 3 ) => 119.37 g/mol

C% =  ( atomic mass C / molar mass CHCl3 ) * 100

For C :

C % =  (12.01 / 119.37 ) * 100

C% = ( 0.1006 * 100 )

C% =  10.06 %

For H :

H% = ( atomic mass H / molar mass CHCl3 ) * 100

H% = ( 1.008 / 119.37 ) * 100

H% = 0.008444 * 100

H% = 0.8444 %

For Cl :

Cl % ( molar mass Cl3 / molar mass CHCl3 ):

Cl% =  ( 3 * 35.45 / 119.37 ) * 100

Cl% =  ( 106.35 / 119.37 ) * 100

Cl% = 0.8909 * 100

Cl% = 89.9%


Hope that helps!

4 0
3 years ago
An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr
Lera25 [3.4K]

Answer:

\sigma_y\ =210.2\ MPa  

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}

\sigma_y\ =Yield\ strength

d = diameter

K =Constant

\sigma_o\ =material\ constant

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

163=\sigma_o+\dfrac{K}{\sqrt 35}      ------------1

d= 17 μm ,yield strength = 192 MPa

192=\sigma_o+\dfrac{K}{\sqrt 17}           ------------2

From equation 1 and 2

192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}

K=394.53

By putting the values of K in equation 1

163=\sigma_o+\dfrac{394.53}{\sqrt 35}

\sigma_o\ =96.31\ MPa

\sigma_y=96.31+\dfrac{394.53}{\sqrt d}

Now when d= 12 μm

\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}

\sigma_y\ =210.2\ MPa

4 0
3 years ago
Under the gold standard, a country in balance-of-trade equilibrium earns income from exports that is equal to the money its resi
solong [7]

The answer is true.

Explanation:

The balance of trade is nothing but the country's exports minus the country's imports.

Exports means, what you produce in the country and sell it to other countries, whereas imports means what you get or buy from the other countries.

When you export more than you import, you have trade surplus .In that case the income from exports are more than the money spent. So you have a trade surplus.

When you import then you have a trade deficit or your income is low. Most of the countries want a trade surplus.

But when the Income from exports and the money spent on imports are the same , the situation is that of balance of trade equilibrium, where the income from exports is equal to the money its residents pay for the imports.

4 0
3 years ago
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