Scientists must be impartial and not base their conclusions on ____. A. opinions B. models C. evidence D. experiments

2 answers:

6 0

Scientists should not base their conclusion of a certain topic or discussion depending on the opinion of other people. As a scientist, someone should based the conclusions on the facts and data gathered through experimentation, models, and evidences. Thus, the answer is A.

shusha [124]3 years ago

5 0

Scientists must be impartial and not base their conclusions on A. Opinions.

You might be interested in

A car passes you at 18 m/s to the north and increases its speed at a rate of 3.0 m/s. Determine the car's velocity when it has a

monitta

122

...................................................................,.......,..................................

8 0

3 years ago

Definition of definite

KIM [24]

Google definition: a statement of the exact meaning of a word, especially in a dictionary.

the degree of distinctness in outline of an object, image, or sound, especially of an image in a photograph or on a screen.

My definition: The meaning or deintion of any word.

5 0

4 years ago

What is the definition of Newton and could you leave an example of it too?

vichka [17]

What is the definition of newton

7 0

3 years ago

This is for 6th grade Science -Geology - weather and climate.

Ierofanga [76]

Answer:

Explanation:

nahh

3 0

3 years ago

A guitar string is supposed to have a fundamental frequency 256 Hz. It currently has a fundamental frequency 248 Hz when the str

umka2103 [35]

Answer:

The tension to bring the guitar string into tune is 372.95 Hz.

Explanation:

Given;

current frequency, f₁ = 248 Hz

current tension, T₁ = 350 N

fundamental frequency, f₂ = 256

The tension on the string to bring the guitar string into tune is calculated as;

$v = \sqrt{\frac{T}{\mu} } \\\\f\lambda = \sqrt{\frac{T}{\mu} } \\\\f^2\lambda^2 = \frac{T}{\mu} \\\\f^2 = \frac{T}{\mu \lambda^2}\\\\let \ {\mu \lambda^2} = k\\\\f^2 =\frac{T}{k} \\\\k = \frac{T}{f^2} \\\\\frac{T_1}{f_1^2} = \frac{T_2}{f_2^2}\\\\T_2 = \frac{T_1 f_2^2}{f_1^2} \\\\T_2 = \frac{350 \times 256^2}{248^2} \\\\T_2 = 372.95 \ Hz$

Therefore, the tension to bring the guitar string into tune is 372.95 Hz.

3 0

3 years ago