All categories

3 years ago

A school determined that about a 67% chance that students will choose chocolate milk over white milk

Mathematics

2 answers:

alexgriva [62]3 years ago

5 0

What the question to this

poizon [28]3 years ago

5 0

Answer:

By rolling the dice

Step-by-step explanation:

You might be interested in

Which domain restrictions apply to the rational expression? x^2+4x+4 / x^2−4 Select each correct answer x≠−4 x≠−2 x≠0 x≠2 x≠4

Degger [83]

The correct answers are x≠2 and x≠(-2).

Domain restrictions are any points in the domain where the function will not have a value. This basically means that it's a point where x won't work in the function.

For the numerator, any value will work for x. We can have a value of 0 in the numerator, or a positive, negative, or decimal number.

However, the denominator cannot equal 0. This is because a fraction bar represents division, and we cannot divide by 0. The values that make the denominator 0 can be found by:

x²-4=0

Add 4 to both sides:
x²-4+4 = 0+4
x² = 4

Take the square root of both sides:
√x² = √4

x = 2 or x = -2.

7 0

3 years ago

Read 2 more answers

Which of the following is an expression for”doubling a number n and dividing by 3”?

kirza4 [7]

Answer:

2n/3

Step-by-step explanation:

hope this helps!! moo

4 0

3 years ago

Solve x2 + 4x − 4 = 0

hoa [83]

Answer:

third option

Step-by-step explanation:

Given

x² + 4x - 4 = 0 ( add 4 to both sides )

x² + 4x = 4

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 4 + 4, that is

(x + 2)² = 8 ( take the square root of both sides )

x + 2 = ± $\sqrt{8}$ = ± 2 $\sqrt{2}$ ( subtract 2 from both sides )

x = - 2 ± 2 $\sqrt{2}$

7 0

3 years ago

Read 2 more answers

In an arithmetic sequence, the nth term an is given by the formula an=a1+(n−1)d, where a1 is the first term and d is the commo

Dmitry_Shevchenko [17]

Answer:

$a_{10} = \frac{10}{65536}$

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

$a_{3} - a_{2} = a_{2} - a_{1}$

We have that:

$a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}$

$a_{3} - a_{2} = a_{2} - a_{1}$

$\frac{5}{2} - 10 = 10 - 40$

$\frac{-15}{2} \neq -30$

This is not an arithmetic sequence.

This sequence is geometric if:

$\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}$

$\frac{\frac{5}[2}}{10} = \frac{10}{40}$

$\frac{5}{20} = \frac{1}{4}$

$\frac{1}{4} = \frac{1}{4}$

This is a geometric sequence, in which:

The first term is 40, so $a_{1} = 40$

The common ratio is $\frac{1}{4}$ , so $r = \frac{1}{4}$ .

We have that:

$a_{n} = a_{1}*r^{n-1}$

The 10th term is $a_{10}$ . So:

$a_{10} = a_{1}*r^{9}$

$a_{10} = 40*(\frac{1}{4})^{9}$

$a_{10} = \frac{40}{262144}$

Simplifying by 4, we have:

$a_{10} = \frac{10}{65536}$

3 0

3 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

spin [16.1K]

The other endpoint is (1, -17).

The midpoint formula is:

$m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Using our midpoint and endpoint, we have:
$(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})
\\
\\6=\frac{11+x_2}{2} \text{ and } -11=\frac{-5+y_2}{2}
$

For the first equation (to find the x-coordinate) we will multiply both sides by 2:
$6\times2=\frac{11+x_2}{2}\times 2
\\
\\12=11+x_2$

Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
1 = x₂

For the second equation (the y-coordinate) we multiply both sides by 2:
$-11\times2=\frac{-5+y_2}{2}\times 2
\\
\\-22=-5+y_2$

Add 5 to both sides:
-22+5 = -5+y₂ + 5
-17 = y₂

This means that (x₂, y₂) is at (1, -17).

4 0

3 years ago