Complete the comparison: 5+4=?

Researchers capture and mark 43 squirrels in a park. The next week, researchers capture 50 squirrels and 38 of them are marked f

Vlada [557]

The question is an illustration of sample and population, and the estimate of the population of squirrel in the park is 55

<h3>How to determine the population of squirrel?</h3>

The given parameters are:

Marked squirrels = 43

Captured squirrels = 50

Of the 50 captured squirrels, 38 are from the marked squirrels.

This means that the number of unmarked squirrels is:

Unmarked = 50 - 38

Evaluate

Unmarked = 12

The population of the squirrel is then calculated using:

Population = Marked + Unmarked

So, we have:

Population = 43 + 12

Evaluate the sum

Population = 55

Hence, the estimate of the population of squirrel in the park is 55

Read more about population at:

brainly.com/question/7301139

#SPJ1

6 0

2 years ago

Evaluate-32 + (2 – 6)(10)<br> The answer is -49

Drupady [299]

Ok thank you I think you answered in the wrong place

8 0

3 years ago

Sharla is moving to New York,she found a movin company that charges a one time fee of $400 and $5 per mile,m.which of the follow

ryzh [129]

5+c=400
- 005
395

C=395

4 0

3 years ago

The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.03 cm.

S_A_V [24]

Answer:

a) P(7.99 ≤ X ≤ 8.01) = 0.8164

b) P(X ≥ 8.01) = 0.0475.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

$\mu = 8, \sigma = 0.03$