T in the independent variable because it does not change based on the other variable. The other variable (C) changes based on it.<span />
Answer:
D=E (Base angle of isosceles triangle are equal)
D+E+F= 180° (sum of angles of a triangle️)
(4x+7)+(4x+7)+(5x+10) = 180
13x = 180- 24
x= 156/13 = 12°
so, E= 4x+7 = 4×12+7 = 55
Hope this helps:)
Answer:
Since the calculated value of t =-0.427 does not fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Step-by-step explanation:
The given data is
Difference d= -24 -12 -55 -15 -30 -60 -14 -21 -48 -12 -25 -53 -61 -69 -80
∑ d= -579
∑d²= 29871
1) Let the hypotheses be
H0: ud= 25 against the claim Ha: ud ≠25
H0 : mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Ha: mean difference in the age of onset of symptoms and age of diagnosis is not 25 months.
2) The degrees of freedom = n-1= 15-1= 14
3) The significance level is 0.05
4) The test statistic is
t= d`/sd/√n
The critical region is ║t║≤ t (0.025,14) = ±2.145
d`= ∑di/n= -579/15= -38.6
Sd= 23.178 (using calculators)
Therefore
t= d`/ sd/√n
t= -38.6/ 23.178√15
t= -1.655/3.872= -0.427
5) Since the calculated value of t =-0.427 does not fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the age of onset of symptoms and age of diagnosis is 25 months .
Ok, so find the least common multiplule betwen 4 and 6
4=2*2
6=2*3
LCM=2*2*3=12
12 days from start
5th
12 days fraom that is 12+5=17
the 17th