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Assoli18 [71]
3 years ago
5

Complete the comparison: 5+4=?

Mathematics
1 answer:
atroni [7]3 years ago
4 0
It could be 
5 + 4 = 3 squared, or
5 + 4 = 3 x3
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Researchers capture and mark 43 squirrels in a park. The next week, researchers capture 50 squirrels and 38 of them are marked f
Vlada [557]

The question is an illustration of sample and population, and the estimate of the population of squirrel in the park is 55

<h3>How to determine the population of squirrel?</h3>

The given parameters are:

Marked squirrels = 43

Captured squirrels = 50

Of the 50 captured squirrels, 38 are from the marked squirrels.

This means that the number of unmarked squirrels is:

Unmarked = 50 - 38

Evaluate

Unmarked = 12

The population of the squirrel is then calculated using:

Population = Marked + Unmarked

So, we have:

Population = 43 + 12

Evaluate the sum

Population = 55

Hence, the estimate of the population of squirrel in the park is 55

Read more about population at:

brainly.com/question/7301139

#SPJ1

6 0
2 years ago
Evaluate-32 + (2 – 6)(10)<br> The answer is -49
Drupady [299]
Ok thank you I think you answered in the wrong place
8 0
3 years ago
Sharla is moving to New York,she found a movin company that charges a one time fee of $400 and $5 per mile,m.which of the follow
ryzh [129]
5+c=400
- 005
395

C=395
4 0
3 years ago
The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.03 cm.
S_A_V [24]

Answer:

a) P(7.99 ≤ X ≤ 8.01) = 0.8164

b) P(X ≥ 8.01) = 0.0475.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 8, \sigma = 0.03

(a) Calculate P(7.99 ≤ X ≤ 8.01) when n = 16.

n = 16, so s = \frac{0.03}{4} = 0.0075

This probability is the pvalue of Z when X = 8.01 subtracted by the pvalue of Z when X = 7.99. So

X = 8.01

Z = \frac{X - \mu}{\sigma}

Applying the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.0075}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 7.99

Z = \frac{X - \mu}{s}

Z = \frac{7.99 - 8}{0.0075}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918

0.9082 - 0.0918 = 0.8164

P(7.99 ≤ X ≤ 8.01) = 0.8164

(b) How likely is it that the sample mean diameter exceeds 8.01 when n = 25? P(X ≥ 8.01) =

n = 25, so s = \frac{0.03}{5} = 0.006

This is 1 subtracted by the pvalue of Z when X = 8.01. So

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.006}

Z = 1.67

Z = 1.67 has a pvalue of 0.9525

1 - 0.9525 = 0.0475

P(X ≥ 8.01) = 0.0475.

4 0
3 years ago
A total of 50 juniors and seniors were given a mathematics test. The 35 juniors attained an average score of 80 while the 15 sen
Alik [6]

Answer:

77

Step-by-step explanation:

Firstly, we need to calculate the total score of the junior students and the total score of the senior students.

The total score of the junior students is 35 * 80 = 2,800

The total score of the senior students is 15 * 70 = 1050

The total score is thus 2,800 + 1,050 = 3,850

The average score of the 50 students is thus 3,850/50 which equals 77

8 0
3 years ago
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