All categories

2 years ago

How do you find the ratio of 2:5...

Mathematics

1 answer:

LuckyWell [14K]2 years ago

4 0

Answer:

total number of parts of a 2:5 ratio are 7 as 2+5 = 7

let us assume are number to be 49

the first part will be 49/7 × 2 = 14

the second part will be 49/7 × 5 = 35

You might be interested in

a red hot ar balloon is 100 feet off the ground and is rising at a rate of 8 feet per second. a green hot air balloon is 160 fee

zhenek [66]

Answer:

it would be a fraction of a sec

Step-by-step explanation:

see if you just simply took out a calculator you would see its not possible unless you knew what the balloon is descending at during the fraction of the seconds

7 0

2 years ago

Canada has a population that is about 1/10 as large as the United States. If Canada's population is about 32,000,000, about how

Nezavi [6.7K]

Canada's populations times 10 and you will get the answer.

8 0

3 years ago

For the given points a(-4 6) and b(6 -4) find the slope of a line through points A and B

kap26 [50]

Answer:

the required slope of the points is -1...

3 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

7 0

2 years ago

Please help me solve the question

ASHA 777 [7]

Is .08 for netx 10 is . 02

5 0

2 years ago