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<h3><u>Answer;</u></h3>
= 75 %
<h3><u>Explanation</u>;</h3>
To measure efficiency of a machine, compare the work output to work input.
Efficiency = Work output/ work output × 100 %
= 300/400 × 100
= 75 %
We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m
Answer:
Approximately 4.5 square miles
Explanation:
(surrounding van Nuys and sepulveda stations) and one measuring approximately 2.85 square miles ( surrounding north Hollywood Station)
For these two questions, first you need to know that the voltage across each branch of a parallel circuit is the same.
So, for Q5, we can first find out the voltage across R₂ by V=IR.
Voltage across R₂ = 2.5 × 8 = 20V
Since R₂ and R₃ are in parallel circuit, their voltage should be the same. Thus, voltage across R₃ is 20V.
So, by V=IR,
current of R₃ =
= 5A
Q6. voltage across R₁ = 2 × 4 = 8V
∴voltage across R₂ = 8V
current of R₂ =
= 1A
<h3><u>Alternative method</u></h3>
From these two examples, you can find out that the current of each branch of the parallel circuit is inversely proportional to the resistance of the branch.
ie. for Q5,
= 
= 
I₃ = 5A
Q6.
= 
= 
I₂ = 1A