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stepan [7]
3 years ago
11

If the Speed limit is 60 mph, if I drive at a speed of 130 km/hr would I maybe get a ticket? (0.621 mi = 1km)

Physics
1 answer:
katovenus [111]3 years ago
5 0

Explanation:

130km = (0.621 * 130) mi = 80.73 mi

So if you drive at 80.73 mph you will get a ticket for speeding over the limit.

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Is the answer 1.05m?? help me please. i just want to confrim my answer :3
grandymaker [24]
I believe you are correct! Have a good day! <3
4 0
2 years ago
What is the efficiency of a tractor that has a work output of 300j and a work input of 400j
Sauron [17]
<h3><u>Answer;</u></h3>

= 75 %

<h3><u>Explanation</u>;</h3>

To measure efficiency of a machine, compare the work output to work input.

Efficiency = Work output/ work output × 100 %

                = 300/400 × 100

                = 75 %

5 0
3 years ago
Calculate the displacement of the volleyball in sample problem 2f when teh volleyballs final velocity is 1.1 m/s upward
stich3 [128]
We have: v i (initial velocity) = 6 m/sv = 1.1 m/sa = - 9.8 m/s²v = v i + a · t1.1 m/s = 6 m/s - 9.8 m/s² t9.8 t = 6 - 1.19.8 t = 4.9t = 4.9 : 9.8t = 0.5 sThen the replacement:x = xi + vi · t + a t² / 2( xi = 0 )x = 6 · 0.5 - 9.8 · 0.25 / 2x = 3 - 1.225Answer:
x = 1.775 m

4 0
3 years ago
Question 1<br> The orange line is measuring the
11111nata11111 [884]

Answer:

Approximately 4.5 square miles

Explanation:

(surrounding van Nuys and sepulveda stations) and one measuring approximately 2.85 square miles ( surrounding north Hollywood Station)

4 0
3 years ago
Help with these questions please , 15 PTS &amp; brainliest
myrzilka [38]

For these two questions, first you need to know that the voltage across each branch of a parallel circuit is the same.

So, for Q5, we can first find out the voltage across R₂ by V=IR.

Voltage across R₂ = 2.5 × 8 = 20V

Since R₂ and R₃ are in parallel circuit, their voltage should be the same. Thus, voltage across R₃ is 20V.

So, by V=IR,

current of R₃ = \frac{20}{4} = 5A

Q6. voltage across R₁ = 2 × 4 = 8V

∴voltage across R₂ = 8V

current of R₂ = \frac{8}{8} = 1A

<h3><u>Alternative method</u></h3>

From these two examples, you can find out that the current of each branch of the parallel circuit is inversely proportional to the resistance of the branch.

ie. for Q5,

\frac{R2}{R3} = \frac{I3}{I2}

\frac{8}{4} = \frac{I3}{2.5}

I₃ = 5A

Q6. \frac{R1}{R2} = \frac{I2}{I1}

\frac{4}{8} = \frac{I2}{2}

I₂ = 1A

6 0
3 years ago
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