Answer:
![9.16rad/s^2](https://tex.z-dn.net/?f=9.16rad%2Fs%5E2)
Explanation:
We are given that
Mass,![m_1=3.3 kg](https://tex.z-dn.net/?f=m_1%3D3.3%20kg)
Radius,r=0.8 m
![m_2=4.9 kg](https://tex.z-dn.net/?f=m_2%3D4.9%20kg)
Height,h=2.9 m
We have to find the angular acceleration of the cylinder.
According to question
![4.9g-T=4.9a](https://tex.z-dn.net/?f=4.9g-T%3D4.9a)
![Tr=I\alpha](https://tex.z-dn.net/?f=Tr%3DI%5Calpha)
Where
![\alpha=\frac{a}{r}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7Ba%7D%7Br%7D)
![Tr=\frac{1}{2}m_1ra](https://tex.z-dn.net/?f=Tr%3D%5Cfrac%7B1%7D%7B2%7Dm_1ra)
![T=\frac{1}{2}m_1a=\frac{1}{2}(3.3)a](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B1%7D%7B2%7Dm_1a%3D%5Cfrac%7B1%7D%7B2%7D%283.3%29a)
Substitute the value
![4.9g-\frac{1}{2}(3.3a)=4.9a](https://tex.z-dn.net/?f=4.9g-%5Cfrac%7B1%7D%7B2%7D%283.3a%29%3D4.9a)
![4.9\times 9.8=4.9a+\frac{3.3a}{2}](https://tex.z-dn.net/?f=4.9%5Ctimes%209.8%3D4.9a%2B%5Cfrac%7B3.3a%7D%7B2%7D)
Where ![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
![48.02=a(4.9+1.65)=6.55a](https://tex.z-dn.net/?f=48.02%3Da%284.9%2B1.65%29%3D6.55a)
![a=\frac{48.02}{6.55}=7.33m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B48.02%7D%7B6.55%7D%3D7.33m%2Fs%5E2)
Angular acceleration,![\alpha=\frac{a}{r}=\frac{7.33}{0.8}=9.16rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7Ba%7D%7Br%7D%3D%5Cfrac%7B7.33%7D%7B0.8%7D%3D9.16rad%2Fs%5E2)
Answer:
a burning piece of converts Chemical energy into Heat(Thermal) and Light energy
Answer:
![F_{net} = 232.8 N](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20232.8%20N)
towards right so it is -15 degree
Explanation:
Net force in forward direction due to all three is given as
![F_x = F_1 + F_2cos45 + F_3cos45](https://tex.z-dn.net/?f=F_x%20%3D%20F_1%20%2B%20F_2cos45%20%2B%20F_3cos45)
here we know that
![F_1 = 77.3 N](https://tex.z-dn.net/?f=F_1%20%3D%2077.3%20N)
![F_2 = 61.7 N](https://tex.z-dn.net/?f=F_2%20%3D%2061.7%20N)
![F_3 = 147 N](https://tex.z-dn.net/?f=F_3%20%3D%20147%20N)
![F_x = 77.3 + 61.7 cos45 + 147 cos45](https://tex.z-dn.net/?f=F_x%20%3D%2077.3%20%2B%2061.7%20cos45%20%2B%20147%20cos45)
![F_x = 224.9 N](https://tex.z-dn.net/?f=F_x%20%3D%20224.9%20N)
Similarly in Y direction we will have
![F_y = F_3 sin45 - F_2 sin45](https://tex.z-dn.net/?f=F_y%20%3D%20F_3%20sin45%20-%20F_2%20sin45)
![F_y = (147 - 61.7)sin45](https://tex.z-dn.net/?f=F_y%20%3D%20%28147%20-%2061.7%29sin45)
![F_y = 60.3 N](https://tex.z-dn.net/?f=F_y%20%3D%2060.3%20N)
Now the net force on the donkey is given as
![F_{net} = \sqrt{F_x^2 + F_y^2}](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20%5Csqrt%7BF_x%5E2%20%2B%20F_y%5E2%7D)
![F_{net} = \sqrt{224.9^2 + 60.3^2}](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20%5Csqrt%7B224.9%5E2%20%2B%2060.3%5E2%7D)
![F_{net} = 232.8 N](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20232.8%20N)
Now direction of force is given as
![tan\theta = \frac{F_y}{F_x}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7BF_y%7D%7BF_x%7D)
![tan\theta = \frac{60.3}{224.9}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7B60.3%7D%7B224.9%7D)
towards right so it is -15 degree
Explanation:
All living organisms metabolize. That is the definition of life. So jr answer is no animal or organism that does not consume food.