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liraira [26]
3 years ago
7

The local newspaper has published the passage below. Last week, scientists released incredible images of aurora australis, known

as the northern lights, as seen from the Hubble telescope. The Hubble telescope was placed in orbit in 1990 by the space shuttle and has since delivered the sharpest images we have of our planet, our galaxy, and the universe. The images delivered last week show the beautiful display of lights in the southern hemisphere. These lights are the result of the solar activity known as solar wind. Traces of solar wind reach well beyond Earth and have been detected as far as Saturn. Which statement in the news passage above is inaccurate
Physics
2 answers:
OverLord2011 [107]3 years ago
6 0

Answer:

The statement as aurora australis known as northern lights is incorrect. As the designation of aurora australis is for the southern lights i.e. which occur in the southern hemisphere.

Explanation:

Aurora or natural lights is a phenomenon that occurs at the poles of the Earth due to interaction between the Earth's magnetic field and cosmic rays. This interaction results in the beautiful display of colors on both poles. These are named, aurora borealis or aurora australis depending on their geographical location. If they occur on the northern pole they are termed as aurora borealis while those occurring on the southern pole are named aurora australis.

defon3 years ago
5 0

Answer:

C. The aurora australis is known as the northern lights.

Explanation

The answer on edge

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what is the gravitational potential energy of a 150-kg object that is suspended 5-m above the earth's surface
77julia77 [94]
150x5x9.7(gravity on earth)=7275
7 0
3 years ago
Water has a very high specific heat capacity when compared to most other common materials. In fact, ethyl alcohol has a specific
AveGali [126]

Answer:

Lead, Ethyl alcohol and water.

Explanation:

Specific heat capacity of a substance can be define as the quantity of heat that is absorbed by a substance needed to change the temperature of a unit mass of one kilogram of the substance by one kelvin

5 0
3 years ago
A ball is shot straight up into the air from the ground with initial velocity of 44ft/sec44ft/sec. assuming that the air resista
solniwko [45]
Convert the given in SI units.

         (44 ft/sec)(1 m/ 3.28 ft) = 13.41 m/sec

The distance traveled and the initial velocity can be related through the equation,
  
   d = (Vf)² - (Vi)²/ 2a

where d is the distance, Vf is the final velocity, Vi is the initial velocity, a is the acceleration due to gravity. Substituting the known values from the given above,

    d = ((0 m/s)² - (13.41 m/s)²)/ 2(-9.8 m/s²)

The value of d from the equation,

    d = 9.17 meters

Convert this to feet,

    d = (9.17 m)(3.28 ft / 1 m) = 30 ft

Answer: 30 ft
3 0
3 years ago
On your first trip to Planet X you happen to take along a 180 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r
lys-0071 [83]

Answer:

g_x = 3.0 m / s^2

Explanation:

Given:

- Change in length of spring [email protected] = 22.6 cm

- Time taken for 11 oscillations t = 19.0 s

Find:

- The value of gravitational free fall g_x at plant X:

Solution:

- We will assume a simple harmonic motion of the mass for which Time is:

                                 T  = 2*pi*sqrt(k / m )    ...... 1

- Sum of forces in vertical direction @equilibrium is zero:

                                 F_net = k*x - m*g_x = 0

                                 (k / m) = (g_x / x)    .... 2

- substitute Eq 2 into Eq 1:

                                  2*pi / T = sqrt ( g_x / x )

                                   g_x = (2*pi / T )^2 * x

- Evaluate g_x:

                                  g_x = (2*pi / (19 / 11) )^2 * 0.226

                                  g_x = 3.0 m / s^2

                                 

                       

3 0
3 years ago
A tank of gasoline (n = 1.40) is open to the air (n = 1.00). A thin film of liquid floats on the gasoline and has a refractive i
klio [65]

Answer:

1.08

Explanation:

This is the case of interference in thin films in which interference bands are formed due to constructive interference of two reflected light waves , one from upper layer and the other from lower layer . If t be the thickness and μ be the refractive index then

path difference created will be 2μ t.

For light coming from rarer to denser medium , a phase change of π occurs additionally after reflection from denser medium, here, two times, once from upper layer and then from the lower layer ,  so for constructive interference

path diff = nλ , for minimum t , n =1

path diff = λ

2μ t. =  λ

μ = λ / 2t

= 626 / 2 x 290

= 1.08

5 0
3 years ago
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