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liraira [26]
3 years ago
7

The local newspaper has published the passage below. Last week, scientists released incredible images of aurora australis, known

as the northern lights, as seen from the Hubble telescope. The Hubble telescope was placed in orbit in 1990 by the space shuttle and has since delivered the sharpest images we have of our planet, our galaxy, and the universe. The images delivered last week show the beautiful display of lights in the southern hemisphere. These lights are the result of the solar activity known as solar wind. Traces of solar wind reach well beyond Earth and have been detected as far as Saturn. Which statement in the news passage above is inaccurate
Physics
2 answers:
OverLord2011 [107]3 years ago
6 0

Answer:

The statement as aurora australis known as northern lights is incorrect. As the designation of aurora australis is for the southern lights i.e. which occur in the southern hemisphere.

Explanation:

Aurora or natural lights is a phenomenon that occurs at the poles of the Earth due to interaction between the Earth's magnetic field and cosmic rays. This interaction results in the beautiful display of colors on both poles. These are named, aurora borealis or aurora australis depending on their geographical location. If they occur on the northern pole they are termed as aurora borealis while those occurring on the southern pole are named aurora australis.

defon3 years ago
5 0

Answer:

C. The aurora australis is known as the northern lights.

Explanation

The answer on edge

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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm . The explorer finds that
larisa86 [58]

Answer:

12.4 m/s²

Explanation:

L = length of the simple pendulum = 53 cm = 0.53 m

n = Number of full swing cycles = 99.0

t = Total time taken = 128 s

T = Time period of the pendulum

g = magnitude of gravitational acceleration on the planet

Time period of the pendulum is given as

T = \frac{t}{n}

T = \frac{128}{99}

T = 1.3 sec

Time period of the pendulum is also given as

T = 2\pi \sqrt{\frac{L}{g}}

1.3 = 2(3.14) \sqrt{\frac{0.53}{g}}

g = 12.4 m/s²

4 0
3 years ago
6)the speed of light is approximately​ 186,000 mi/sec. It takes light from a particular star approximately 9 yrs to reach Earth.
NeTakaya

Answer:

5.2791264*10¹³

Explanation:

Convert the 9 years to seconds and then multiple it by 186000

5 0
3 years ago
If the total time is 120 seconds and the total distance is 320 meters. Calculate
RUDIKE [14]

Answer:

S=D/T

320/120= 2.66 miles

Explanation:

3 0
3 years ago
What is the area under the curve for the histogram below?
olga2289 [7]
Well i honestly wouldn’t know
5 0
3 years ago
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Light is incident along the normal to face AB of a glass prism of refractive index 1.54. Find αmax, the largest value the angle
marusya05 [52]

To solve this problem it is necessary to use the concepts related to Snell's law.

Snell's law establishes that reflection is subject to

n_1sin\theta_1 = n_2sin\theta_2

Where,

\theta = Angle between the normal surface at the point of contact

n = Indices of refraction for corresponding media

The total internal reflection would then be given by

n_1 sin\theta_1 = n_2sin\theta_2

(1.54) sin\theta_1 = (1.33)sin(90)

sin\theta_1 = \frac{1.33}{1.54}

\theta = sin^{-1}(\frac{1.33}{1.54})

\theta = 59.72\°

Therefore the \alpha_{max} would be equal to

\alpha = 90\°-\theta

\alpha = 90-59.72

\alpha = 30.27\°

Therefore the largest value of the angle α is 30.27°

3 0
3 years ago
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