Question

A current of 2.50 amps is passed through an electrolytic cell containing a solution of M(NO3)2, where M represents an unidentified metal. The only reaction that occurs at the cathode is the deposition of the unknown metal. After 2.00 hours, 5.93 g of the metal has been deposited.
Required:
Determine the chemical symbol of the metal.

Answer 1

Answer:

The chemical symbol will be "$_{29}^{63.5}\textrm{Cu}$".

Explanation:

The given values are:

Current,

I = 2.50 amps

Time,

t = 2 hr

or,

 = 7200 sec

Metal deposited,

W = 5.93 gm

As we know,

⇒  $W=Z\times i\times t$

or,

⇒  $Z=\frac{W}{i\times t}$

On putting the given values, we get

⇒      $=\frac{5.93}{2.5\times 7200}$

⇒      $=3.2945\times 10^{-4}$

hence,

⇒ $Atomic \ mass=Z\times electrons\times 96500$

⇒                       $=3.2945\times 10^{-4}\times 2\times 96500$

⇒                       $=63.5$

Thus the above is the right answer.