Oil keeps the moving metal parts of an engine smoothly rubbing together through lubrication. Just like with other mechanical devices, energy can be lost due to friction caused by lack of proper lubrication. When an engine is running on old or insufficient oil, more friction and heat is produced between the rubbing moving parts. A decline in gas mileage follows this since the fuel takes more than usual to do the same task.
silt because it occurs in regular flooded areas, and is high in nutrients.
For starters, this question isn’t really about relativity. It’s about
energy, and E=mc^2 only makes sense if energy has the units of
(mass)*(velocity)^2. So we might as well ask: why is kinetic energy
defined as KE = ½*mv^2?
Answer:
Explanation:
(a) the angle between the coil and the coil's magnetic dipole moment is same that means zero degree.
(b) L = 17.6 cm = 0.176 m
i = 5.95 mA = 5.95 x 106-3 A
B = 4.74 mT = 4.74 x 10^-3 T
(b) Let r be the radius of the loop is r
Circumference = 2 x 3.14 x r
0.176 = 2 x 3.14 x r
r = 0.028 m
B = μo/4π x (N x 2 π i) / r
Where, N be the number of turns
4.74 x 10^-3 = (10^-7 x N x 2 x 3.14 x 5.95 x 10^-3) / 0.028
N = 3.55 x 10^4
(c) Maximum torque = N i A B
τ = 3.55 x 10^4 x 5.95 x 10^-3 x 3.14 x 0.028 x 0.028 x 4.74 x 10^-3
τ = 2.465 x 10^-3 Nm
Answer:
vf = 14.2176 m/s
Explanation:
Given
m = 4 Kg
viy = 7.00 ĵ m/s
Fx = 11.0 î N
t = 4.5 s
vf = ?
Using the Impulse - Momentum Theorem, we have
F*Δt = m*Δv ⇒ F*Δt = m*(vf - vi)
⇒ vf = (F*Δt + m*vi) / m
⇒ vf = (F*Δt + m*vi) / m
For <em>x-component</em>
⇒ vfx = (Fx*Δt + m*vix) / m = (11 N*4.5 s + 4 Kg*0 m/s) / (4 Kg)
⇒ vfx = 12.375 î m/s
For <em>y-component</em>
⇒ vfy = (Fy*Δt + m*viy) / m = (0 N*4.5 s + 4 Kg*7 m/s) / (4 Kg)
⇒ vfy = 7 ĵ m/s
Finally:
vf = √(vfx² + vfy²)
⇒ vf = √((12.375 m/s)² + (7 m/s)²)
⇒ vf = 14.2176 m/s
