Answer:
direct current
Explanation:
it has a direct path to go down to reach the specific point
Considering that while traveling on a road with a<u> final speed of 15 m/s</u>, and an<u> initial speed of 24 m/s</u>, with a given time <u>of 12 seconds.</u>
To calculate the acceleration, we apply the following formula:
α = Vf - Vo/t
We add our data into the formula and solve:
α = 15 m/s - 24 m/s/12 sec
α = -0.75 m/s²
Therefore, the acceleration of the car is -0.75 m/s².
<h2>Skandar</h2>
Answer:
assuming the air resistance = 0
so the acceleration is almost constant at 9.82 m/s²
Answer:
a) T = (2,375 ± 0.008) s
, b) When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Explanation:
a) The period of a simple pendulum is
T = 2π √ L / g
Let's calculate
T = 2π √1.40 / 9.8
T = 2.3748 s
The uncertainty of the period is
ΔT = dT / dL ΔL
ΔT = 2π ½ √g/L 1/g ΔL
ΔT = π/g √g/L ΔL
ΔT = π/9.8 √9.8/1.4 0.01
ΔT = 0.008 s
The result for the period is
T = (2,375 ± 0.008) s
b) the experimental measure was T = 2.39 s ± 0.01 s
The theoretical value is comprised in a range of [2,367, 2,387] when we approximate this measure according to the significant figures the interval remains [2,37, 2,39].
When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Answer:
897
Explanation:
Speed of the car, v = 126 km/h, converting to m/s, we have v = 35 m/s and
Radius of the curve, R = 150 mm = 0.15 m
The centripetal acceleration a(c) is given by the formula = v² / R so that
a(c) = 35² / 0.15
a(c) = 1225 / 0.15
a(c) = 8167 m/s²
The force that causes the acceleration is frictional force = µ m g, where
µ = coefficient of friction
m = the mass of the car and
g = acceleration due to gravity, 9.81
From Newton's law:
µ m g = m a(c) , so that
µ = a(c) / g
µ = 8167 / 9.81
µ = 897
Therefore, the coefficient of static friction must be as big as 897
