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1 year ago

What is the velocity of a 50 kg dog with 3000 j of kinetic energy

Physics

2 answers:

mezya [45]1 year ago

8 0

Answer:

KE = 225000000 J

Explanation:

Sergio039 [100]1 year ago

4 0

Answer:

10.954. from equation. KE=1/2m(v^2)

2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50

(v^2)=120. square root for all v=10.954 m/s

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The radioactive 60co isotope is used in nuclear medicine to treat certain types of cancer. Calculate the wavelength and frequenc

Ivanshal [37]

1. Frequency: $3.23\cdot 10^{20} Hz$

The energy given is the energy per mole of particles:

$E=1.29\cdot 10^{11} J/mol$

1 mole contains a number of Avogadro of particles, $N_A$ , equal to

$N_A=6.022\cdot 10^{23}$ particles

So, by setting the following proportion, we can calculate the energy of a single photon:

$1.29 \cdot 10^{11} J/mol : 6.022 \cdot 10^{23} ph/mol = E_1 : 1 ph\\E_1 = \frac{(1.29\cdot 10^{11} J/mol)(1 ph)}{6.022\cdot 10^{23} ph/mol}=2.14\cdot 10^{-13} J$

This is the energy of a single photon; now we can calculate its frequency by using the formula:

$E_1 = hf$

where

$h=6.63\cdot 10^{-34} Js$ is the Planck's constant

f is the photon frequency

Solving for f, we find

$f=\frac{E_1}{h}=\frac{2.14\cdot 10^{-13} J}{6.63\cdot 10^{-34} Js}=3.23\cdot 10^{20} Hz$

2. Wavelength: $9.29\cdot 10^{-13} m$

The wavelength of the photon is given by the equation:

$\lambda=\frac{c}{f}$

where

$c=3\cdot 10^8 m/s$

is the speed of the photon (the speed of light). Substituting,

$\lambda=\frac{3 \cdot 10^8 m/s}{3.23\cdot 10^{20} Hz}=9.29\cdot 10^{-13} m$

6 0

2 years ago

Help please!!!

exis [7]

Answer:

5 years worth of work (aka all of the homework i currently have)

3 0

3 years ago

Two cylinders with the same mass density rhoC = 713 kg / m3 are floating in a container of water (with mass density rhoW = 1025

Tanzania [10]

Answer:

Explanation:

Given

density of cylinder is $\rho _c=713 kg/m^3$

Length of first cylinder is $L_1=20 cm$

radius $r_1=5 cm$

For cylinder 2 $L_2=10 cm$

$r_2=10 cm$

$h_1$ and $h_2$ are the height above water

as object is floating so its weight must be balanced with buoyant force

$\rho _c\frac{\pi }{4}d_1^2L_1g=\rho _w\frac{\pi }{4}d_1^2(L_1-h_1)g----1$

For 2nd cylinder

$\rho _c\frac{\pi }{4}d_2^2L_2g=\rho _w\frac{\pi }{4}d_2^2(L_2-h_2)g----2$

Dividing 1 and 2 we get

$\frac{L_1}{L_2}=\frac{L_1-h_1}{L_2-h_2}$

$\frac{20}{10}=\frac{20-h_1}{10-h_2}$

$2h_2=h_1$

$\\\Rightarrow\frac{h_2}{h_1}=\frac{1}{2}$

5 0

2 years ago

Determine the value of the resistor r so that a current of 0.5a flows through the load.

iren2701 [21]

What is the value of the voltage? There must be one somewhere.

This might be too simple minded, but I'll give it a voltage of 10 Volts.

R = voltage / Current
R = 10 / 0.5
R = 20 volts.

Perhaps you could post a diagram if this is a Kirchhoff Law Question.

8 0

2 years ago

can cuclin concentration durng mitosis be explained by the fact that the cell divides in two and thus divides the material in th

lana [24]

Answer: No

Can the change in cyclin concentration during mitosis be explained by the fact that the cell divides in two and thus divides the material in the cell into two smaller volumes?

Explanation: The cyclin concentration is not halved but degraded during mitosis.

There is an increase in cyclin concentrations at interphase. These changes are caused by the presence of Cyclin Dependent Kinase (CDK) complexes. CDK being a substrate of cyclin catalyses cyclin, thereby increasing its concentration. During mitosis, cyclins are destroyed, signifying the end of mitosis and cytokinesis.

Without this process, it will be impossible for the cell to exit mitosis.

5 0

2 years ago