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chubhunter [2.5K]
3 years ago
9

A 2.51 kg ball is attached to a ceiling by a 1.19 m long string. The height of the room is 3.45 m. The acceleration of gravity i

s 9.81 m/s 2 . What is the gravitational potential energy associated with the ball relative to a) the ceiling?
Physics
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

55,42 J

Explanation:

Since the height of the room is 3.45 m (distance between the floor and the ceiling) the difference between this value and the length of the rope 1.19 m; it will be equal to (3.45-1.19) =2.26 m. If we take as a reference point (Ep=0) the floor of the room, then the potential energy will be equal to Ep = M * g * h, replacing values in this equation (2.5 kg * 9.81 m/s2 * 2.26 m) will be 55,42 (N * m) or Jules.

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Here, we are required to find the relationship between balls of different mass(a measure of weight) and different volumes.

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Mathematically;.

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For Case 1:

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For Case 2:

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Read more:

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2 years ago
A spring with a spring constant of 350 N/m pulls a door closed. How much work is done as the spring pulls the door at a constant
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The work done to stretch the spring will be 112 J.

<h3>What is spring force?</h3>

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

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The work is done to stretch the spring is;

\rm W= \frac{1}{2} kx^2 \\\\ W=\frac{1}{2} \times 350 \times (0.850-0.050)^2 \\\\ W=0.5 \times 350 \times (0.80)^2 \\\\W=112 \ J

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