Explanation:
will dissociate into ions as follows.

Hence,
for this reaction will be as follows.
![K_{sp} = [Pb^{2+}][Br^{-}]^{2}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BPb%5E%7B2%2B%7D%5D%5BBr%5E%7B-%7D%5D%5E%7B2%7D)
We take x as the molar solubility of
when we dissolve x moles of solution per liter.
Hence, ionic molarities in the saturated solution will be as follows.
=
+ x
=
+ 2x
So, equilibrium solubility expression will be as follows.
=
Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains
= 0.10 and there will be no lead ions. So,
= 0
So,
will approximately equals to
.
Hence, ![K_{sp} = x[Br^{-}]^{2}_{o}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20x%5BBr%5E%7B-%7D%5D%5E%7B2%7D_%7Bo%7D)

x =
M
Thus, we can conclude that molar solubility of
is
M.
Answer:
+/- 0.00033
Explanation:
For a 95 % confidence interval the range is given by
+/- Z * s/sqrt(n)
where Z value is 1.916 for a 95% confidence interval
Therefore the interval is
s is the standard deviation in this case 0.0015
n is 75 the number of outposts
calculating,
+/- 1.916 * 0.0015/sqrt(75) = +/- 0.00033
Answer:
A. 2NO + O2 -> 2NO2
B. 4Co + 3O2 -> 2Co2O3
C. 2Al + 3Cl2 -> Al2Cl6
D. 2C2H6 + 7O2 -> 4CO2 + 6H2O
E. TiCl4 + 4Na -> Ti + 4NaCl
Products are the species formed from chemical reactions. During a chemical reaction reactants are transformed into products after passing through a high energy transition state. This process results in the consumption of the reactants.
Answer:
1000 g
Explanation:
d = m/v
We are given d: 10g/cm3
and v: 100cm3
Plug them into the equation to get 10 = m/100
Then, cross multiply 10x100 to get mass which is: 1000g