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Aloiza [94]
2 years ago
8

Hard water stains in sinks and showers can be caused by a buildup of solid calcium carbonate. These stains can be removed by bat

hroom cleaners containing acids such as aqueous hydrochloric acid, which reacts with the calcium carbonate to form carbon dioxide gas, aqueous calcium chloride and liquid water. a) Write a balanced equation for this reaction
Chemistry
2 answers:
LiRa [457]2 years ago
8 0

Answer:

CaCO3 + 2HCl ---> CaCl2 + H2O + CO2

Explanation:

The reaction between solid calcium carbonate and a mineral acid such as aqueous HCl is a neutralization reaction and occurs with the evolution of CO2 gas.

The balanced equation is given below

CaCO3 + 2HCl ---> CaCl2 + H20 + CO2

The product CaCl2 is water soluble which accounts for why the stain is removed, while CO2 gas escapes away from the reaction surface.

LenaWriter [7]2 years ago
7 0

Answer:

CaCO3(s) + 2HCl(aq) -------> CaCl2(aq) + 2CO2(g) + H2O(l)

Explanation:

CaCO3(s) + 2HCl(aq) -------> CaCl2(aq) + 2CO2(g) + H2O(l)

When an acid reacts with a metal carbonate a salt, carbon dioxide and water are formed. Hard water usually contain Ca^2+ in the form of Ca(HCO3)2. Minor heating causes CaCO3(calcium carbonate) to deposit on surfaces through which the hard water passes.

Calcium carbonate reacts with acids to produce a calcium salt, water and carbon dioxide: Calcium carbonate + Hydrochloric acid → Calcium chloride + Water + Carbon dioxide. The carbonate radical breaks up into carbon dioxide and oxygen; the oxygen binds with the acid's hydrogen ions to make water; and a solution of calcium chloride remains.

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Answer:

             66 g of CO₂

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The Balance Chemical Reaction is as follow,

                             C₂H₂  +  5/2 O₂    →    2 CO₂  +  H₂O

Or,

                             2 C₂H₂  +  5 O₂    →    4 CO₂  +  2 H₂O    -------  (1)

Step 1: Find out the limiting reagent as;

According to Equation 1,

            56.1 g (2 mole) C₂H₂ reacts with  =  160 g (5 moles) of O₂

So,

                  125 g of C₂H₂ will react with  =  X g of O₂

Solving for X,

                      X =  (125 g × 160 g) ÷ 56.1 g

                      X =  356.5 g of O₂

It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.

Step 2: Calculate Amount of CO₂ produced as;

According to Equation 1,

              160 g (5 mole) O₂ produces  =  176 g (4 moles) of CO₂

So,

                  60.0 g of O₂ will produce  =  X g of CO₂

Solving for X,

                      X =  (60.0 g × 176 g) ÷ 160 g

                      X =  66 g of CO₂

8 0
3 years ago
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