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katen-ka-za [31]
3 years ago
9

A very small sphere with positive charge 5.00uC is released from rest at a point 1.20cm from a very long line of uniform linear

charge density 3.00 uC/m.. . What is the kinetic energy of the sphere when it is 4.50cm from the line of charge if the only force on it is the force exerted by the line of charge?
Physics
1 answer:
JulijaS [17]3 years ago
5 0
Let us situate this on the x axis, and let our uniform line of charge be positioned on the interval <span>(−L,0]</span> for some large number L. The voltage V as a function of x on the interval <span>(0,∞)</span> is given by integrating the contributions from each bit of charge. Let the charge density be λ. Thus, for an infinitesimal length element <span>d<span>x′</span></span>, we have <span>λ=<span><span>dq</span><span>d<span>x′</span></span></span></span>.<span>V(x)=<span>1/<span>4π<span>ϵ0</span></span></span><span>∫line</span><span><span>dq/</span>r</span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>∫<span>−L</span>0</span><span><span>d<span>x/</span></span><span>x−<span>x′</span></span></span>=<span>λ/<span>4π<span>ϵ0</span></span></span><span>(ln|x+L|−ln|x|)</span></span>
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exis [7]

Answer:

magnitude of v = 2.5 m/s, and in the same direction as the initial velocity of the 5 kg ball.

Explanation:

We use conservation of linear momentum in an elastic collision to solve for the unknown velocity v:

Pi = Pf

5 kg * 5 m/s + 10 kg * 0 m/s = 5 kg * 0 m/s + 10 kg * v

25 kg m/s = 10 kg * v

v = 25/10 m/s

v = 2.5 m/s

and in the same direction as the initial velocity of the 5 kg ball.

7 0
2 years ago
After the elevator accelerates, then it moves at a constant speed of 6.0m/s, calculate the tension inthe cable.
Anon25 [30]

We know that

• The mass of the elevator is 5000 kg.

Let's draw a free-body diagram.

As you can observe, there are just two forces involved, the weight of the elevator and the tension force. Let's use Newton's Second Law.

\begin{gathered} \Sigma F_y=ma_y \\ T-W=ma_y \end{gathered}

But, W = mg = 5000kg*9.8m/s^2 = 49,000 N, and m = 5000 kg, a = 0 (because the speed is constant).

\begin{gathered} T-49,000N=5000\operatorname{kg}\cdot0 \\ T=49,000N \end{gathered}<h2>Therefore, the tension in the cable is 49,000 N.</h2>

3 0
1 year ago
A Tesla Roadster car accelerates from rest at a rate of 7.1m/s for a time of 3.9s
liberstina [14]

The distance covered is 54.0 m

Explanation:

Since the motion of the car is a uniformly accelerated motion, we can use the following suvat equation:

s=ut+\frac{1}{2}at^2

where

u is the initial velocity

t is the time

a is the acceleration

s is the distance covered

For the car in this problem, we have

u = 0 (it starts from rest)

a=7.1 m/s^2 is the acceleration

t = 3.9 s is the time

Substituting, we find s:

s=0+\frac{1}{2}(7.1)(3.9)^2=54.0 m

Learn more about accelerated motion:

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3 years ago
Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are sepa
WINSTONCH [101]

.Answer:

491.4 nm

Explanation:

The distance between central and first maxima is,

y=0.455m

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L=1.62 m

Now the angle can be find as,

tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62})  \\\theta=15.68^{\circ}

Now the grating distance is,

d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m

Now with m=1 condition will become,

\lambda=dsin\theta

So,

\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm

Therefore the wavelength of laser light is 491.4 nm.

3 0
2 years ago
Define thermodynamics ??? ​
BartSMP [9]

Answer:

The term thermodynamics comes from the Greek words therme (heat)  and dynamis (force)

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Energy can be considered as the ability to cause change.

The term thermodynamics comes from the Greek words therme (heat)  and dynamis (force), which corresponds to the most descriptive of the first  efforts to convert heat into energy. At present, the concept is  interpret broadly to include Energy Aspects and their transformations,  including power generation, cooling and relationships  among the properties of matter.

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3 years ago
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