Answer:
Explanation:
Given:
length of ladder 
weight of ladder 
position of firefighter 
weight of firefighter 
angle of ladder 
Unknown:
force of the wall on the ladder 
force of friction on base of ladder 
normal force on base of ladder 
From the free body diagram of the sketch you get 3 equations:

Solving the equations gives:

a)

b)

c) Using the result from b and solving for 

i just took the test on edg enuity it was B.The mass of the rocket decreases as fuel is burned, so the acceleration increases.
Answer:
I would have to say the answer is D
Explanation:
because the angle is being changed using the ray box.
Answer:
a)P₂ =4 bar
b)W= - 1482.48 KJ
It means that work done on the system.
c)S₂ - S₁ = 3.42 KJ/K
Explanation:
Given that
T₁ = 300 K ,V₁ = 3 m³ ,P₁=2 bar
T₂ = 600 K ,V₂=V₁ 3 m³
Given that tank is rigid and insulated.It means that volume of the gas will remain constant.
Lets take the final pressure = P₂
For ideal gas P V = m R T



P₂ =4 bar
Internal energy
ΔU = m Cv ΔT
Cv=0.71 KJ/kg.k for air


m= 6.96 kg
ΔU= 6.96 x 0.71 x (600 - 300)
ΔU=1482.48 KJ
From first law
Q= ΔU + W
Q= 0 Insulated
W = - ΔU
W= - 1482.48 KJ
It means that work done on the system.
Change in the entropy


S₂ - S₁ = 3.42 KJ/K