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Anestetic [448]
2 years ago
14

Which of the following does not serve as a way to neutralize the charge in a body? Question 3 options: A) Bringing the charged b

ody into contact with another body having an equal but opposite charge B) Adding more protons to a positively charged body until the number of protons matches the number of electrons C) Adding free electrons to a positively charged body D) Allowing free electrons to escape from a negatively charged body
Chemistry
1 answer:
Lelechka [254]2 years ago
8 0

Answer: B. Adding more protons to a positively charged body until the number of protons matches the number of electrons

Explanation:

took test got it right

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What must happen for an electron to return to its original energy level from a higher energy level?
attashe74 [19]

An electron should emit energy to return to its original energy level from a higher energy level.

<h3>What is an energy level?</h3>

Energy levels (also called electron shells) are fixed distances from the nucleus of an atom where electrons may be found.

The electron absorbs the energy and jumps to a higher energy level. In the reverse process, emission, the electron returns to the ground state by releasing the extra energy that is absorbed.

Hence, an electron should emit energy to return to its original energy level from a higher energy level.

Learn more about the energy level here:

brainly.com/question/17396431

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3 0
2 years ago
The product side of a chemical reaction is shown.
stealth61 [152]

Answer:

7

Explanation:

The coefficient is the number in front of the chemical symbol.

6 0
2 years ago
How many atoms are in 1.14 mol of sulfur trioxide
yawa3891 [41]
2.75 x 10^24

Hope this helped :)
8 0
3 years ago
1.
german

Order of metals from least reactive to most reactive: B <C <A <D

<h3>Further explanation</h3>

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

Let's analyze the statement in the problem

I. Only A, C and D react with 1 mol/L HCl to give H₂(e)

M + HCl ⇒ MCl + H₂(MCl : alkali, MCl₂ : alkaline earth)

A, C and D can react with 1 mol / L HCl, meaning metals A, C and D are located to the left of element H (more reactive), and B in the right of element H

II. When A is added to solutions of the other metal ions, metallic B and C are  formed but not D.

This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive

3 0
2 years ago
True or false the si in sih4 does not follow the octet rule because hydrogen is in an unusual oxidation stat
ExtremeBDS [4]
The statement is true. The octet rule refers to the general rule of thumb wherein atoms of main-group elements tend to bond with other atoms in such a way that each atom possesses eight electrons (octet) in their valence shell. They tend to form the same electronic configuration as the noble gases. However, there are some exceptions to this rule. One of which is silane, SiH₄. A hydrogen atom only has 1 valence electron and needs another electron to complete its energy level. This is unlike other atoms, for example, carbon which has 4 valence electrons and needs to form 4 covalent bonds to fill its energy levels. Thus, 4 hydrogen atoms need only 4 more electrons. This is given by the silicon atom which has 4 valence electrons. Therefore, when a silicon atom is bonded to 4 hydrogen atoms, the resulting molecule, SiH₄, is a stable one.
6 0
3 years ago
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