1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anestetic [448]
2 years ago
14

Which of the following does not serve as a way to neutralize the charge in a body? Question 3 options: A) Bringing the charged b

ody into contact with another body having an equal but opposite charge B) Adding more protons to a positively charged body until the number of protons matches the number of electrons C) Adding free electrons to a positively charged body D) Allowing free electrons to escape from a negatively charged body
Chemistry
1 answer:
Lelechka [254]2 years ago
8 0

Answer: B. Adding more protons to a positively charged body until the number of protons matches the number of electrons

Explanation:

took test got it right

You might be interested in
For the reaction KClO2⟶KCl+O2 KClO2⟶KCl+O2 assign oxidation numbers to each element on each side of the equation. K in KClO2:K i
frosja888 [35]

Answer:

Explanation:

The formula of the reaction:

            KClO₂ → KCl + O₂

To assign oxidation numbers, we have to obey some rules:

  1. Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
  2. The charge on simple ions signifies their oxidation number.
  3. The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.

The oxidation number of K in KClO₂:

                                   K + (-1) + 2(-2) = 0

                                    K-5 = 0

                                    K = +5

The oxidation number of K in KCl:

                                K + (-1) = 0

                                K = +1

The oxidation number Cl in KClO₂ is -1

For Cl in KCl, the oxidation number is -1

For O in KClO₂, the oxidation number is (2 x -2) = -4

For O in O₂, the oxidation number is 0

K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.

O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.

7 0
3 years ago
Read 2 more answers
The chemical bonds of carbohydrates and lipids have high potential energy because:
gladu [14]

Answer:

c. Many of their bonds are C-C and C-H

Explanation:

The majority of bonds in  carbohydrates and lipids( being an organic compound) are C-C and C-H. Like glucose, fructose or galactose ,etc.

These bonds are strong and do require a lot of energy to break. Thus, a lot of energy are required to break carbs and lipids into simpler compounds.Therefore, carbohydrates and lipids have high potential energy.

The correct answer is c.

4 0
3 years ago
Which of the following additions to alkenes occur(s) specifically in an syn fashion?
BlackZzzverrR [31]

Answer:

E) A, B, and C

Explanation:

Syn addition refers to the addition of two substituents on the same face or side of a double bond. This differed from anti addition which a occurs across opposite face of the double bond.

Hydrogenation, hydroboration and dihydroxylation all involve syn addition to the double bond, hence the answer chosen above.

8 0
2 years ago
12. Your client is prescribed Lipitor for high cholesterol, but has trouble swallowing a whole pill. How do you know Lipitor is
natima [27]

Answer:

The answer is C

Explanation:

This is the answer because it is the only way that it is okay to split in half.

3 0
3 years ago
1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction
nikklg [1K]

Answer:

H_{comb}=-4406kJ/mol

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol

Best regards.

4 0
3 years ago
Other questions:
  • Suppose that atom x undergoes radioactive decay that results in atom y. If y has a larger atomic number than x, which type of ra
    13·1 answer
  • How much silver is produced is 15.00 grams of cu is added to the solution of excess silver nitrate?
    9·1 answer
  • Methionine, ch3sch2ch2ch(nh2)co2h, is an amino acid found in proteins. what is the hybridization type of each carbon, oxygen, th
    7·1 answer
  • Describe the energy inputs and outputs for the campfire. Use the law of conservation of energy to construct a valid qualitative
    9·1 answer
  • The concentration in (M) of bromide ions ina
    6·1 answer
  • How many moles are there in 34.8 grams of Calcium?
    7·1 answer
  • Is there a polyatomic ion in calcium phosphide ?
    15·1 answer
  • The phase change between white tin and gray tin is difficult to observe directly. Both substances can be burned, however. From t
    14·1 answer
  • What's common to H20,HF and NH3​
    11·1 answer
  • Which of the following best describes the forces when there are different-sized forces from opposite directions acting on an obj
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!