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kirill115 [55]
3 years ago
10

Consider the reaction. Upper H subscript 2 upper o (g) plus upper C l subscript 2 upper O (g) double-headed arrow 2 upper H uppe

r C l upper O (g). At equilibrium, the concentrations of the different species are as follows. [H2O] = 0.077 M [Cl2O] = 0.077 M [HClO] = 0.023 M What is the equilibrium constant for the reaction at this temperature?
Chemistry
2 answers:
Vlad [161]3 years ago
6 0

Answer:

0.089

Explanation:

Step 1:

The balanced equation for the reaction is given below:

H2O + Cl2O <=> 2HClO

Step 2:

Data obtained from the question. This includes:

Concentration of H2O, [H2O] = 0.077 M

Concentration of Cl2O, [Cl2O] = 0.077 M

Concentration of HClO, [HClO] = 0.023 M

Equilibrium constant, K =?

Step 3:

Determination of the equilibrium constant. This is illustrated below:

The equilibrium constant for the above reaction is given below:

K = [HClO]^2 / [H2O] [Cl2O]

K = (0.023)^2 / (0.077 x 0.077)

K = 0.089

Therefore, the equilibrium constant for the above reaction is 0.089

dedylja [7]3 years ago
5 0

Answer:

Equilibrium constant for the reaction is 0.0892

Explanation:

This is the reaction of equilibrium

         H₂O      +     Cl₂O     ⇄    2HClO

Eq   0.077M       0.077M           0.023M

Let's make the expression for Kc

Kc = [HClO]² / [Cl₂O] . [H₂O]

Kc= 0.023² / 0.077 . 0.077 = 0.0892

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Answer:

2 H⁺ + 2e = H₂    ( reduction )

Explanation:

Fe( s ) + 2 CH₃COOH = Fe ( OOCCH₃ ) ₂ + H₂

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2 H⁺ + 2e = H₂    ( reduction )

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Calculate the molar mass of carbon tetrafluoride (CF4) in grams per mole, rounding to proper significant figures, if mc= 12.01 u
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Hope this helps

3 0
3 years ago
Read 2 more answers
A sample of carbon dioxide gas occupies a volume of 250 mL at 25c what volume will it occupy at 95c
anzhelika [568]

Considering the Charles's law, the sample of carbon dioxide gas will occupy 308.72 mL.

<h3>Charles's law</h3>

Charles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

Mathematically, Charles's law states that the ratio between volume and temperature will always have the same value:

\frac{V}{T} =k

Considering an initial state 1 and a final state 2, it is fulfilled:

\frac{V1}{T1} =\frac{V2}{T2}

<h3>Final volume in this case</h3>

In this case, you know:

  • V1= 250 mL
  • T1= 25 C= 298 K (being 0 C=273 K)
  • V2= ?
  • T2= 95 C= 368 K

Replacing in Charles's law:

\frac{250 mL}{298 K} =\frac{V2}{368 K}

Solving:

V2=368 K\frac{250 mL}{298 K}

<u><em>V2= 308.72 mL</em></u>

Finally, the sample of carbon dioxide gas will occupy 308.72 mL.

Learn more about Charles's law:

brainly.com/question/4147359

#SPJ1

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