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2 years ago

Through which of the following ways can heat be transferred?

Chemistry

1 answer:

natka813 [3]2 years ago

3 0

Answer: Heat can be transferred in a variety of ways including direct contact so the answer is b

Explanation:title

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How does an ionic bond differ from a covalent bond?

Usimov [2.4K]

Answer:

Ionic bonds transfer electrons and covalent bonds share electrons.

Explanation:

Ionic bonds tend to transfer electrons completely. Take NaCl for example.

Cl has 7 valence electrons.

Na has 1 valence electron.

To stabilize themselves, either with a full 8 shells or full outer shell, Cl wants 1 electron and Na wants to lose 1 electron. So when NaCl forms, Na donates its electron to Cl.

In a covalent bond, the electrons are shared. Water can be used as an example. The electrons in water usually are around the oxygen, but sometimes it is around the hydrogens.

6 0

3 years ago

Which region is colored purple in this periodic table of the elements? A. metals B. metalloids C. nonmetals D. noble gases

icang [17]

Answer:

metals or A

Explanation:

3 0

3 years ago

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Write and balance sodium when it burns in air to form sodium peroxide

Zanzabum

Answer:7.229 grams of oxygen is formed by the complete reaction of 35.23 g of metallic sodium with oxygen at 130–200 °C, a process that generates sodium oxide, which in a separate stage absorbs oxygen: 4 Na + O2 → 2 Na2O. The ozone oxidizes the sodium to form sodium peroxide.

7 0

2 years ago

16. Which of the following aqueous solutions contains the greatest number of 10ns.

gavmur [86]

Answer:

$\boxed{\text{b) 300.0 mL of 0.10 mol/L CaCl}_{2}}$

Explanation:

a) 400.0 mL of 0.10 M NaCl

(i) Moles of NaCl

$\text{ Moles of NaCl } = \text{0.4000 L NaCl} \times \dfrac{\text{0.10 mol NaCl}}{\text{1 L NaCl}} = \text{0.040 mol NaCl}$

(ii) Moles of ions

NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)

We get 2 mol of ions from 1 mol of NaCl

$\text{Moles of ions } = \text{0.040 mol NaCl} \times \dfrac{\text{2 mol ions}}{\text{1 mol NaCl}} = \text{0.080 mol ions}$

b) 300.0 mL of 0.10 M CaCl₂

(i) Moles of CaCl₂

$\text{ Moles of CaCl}_{2} =\text{0.3000 L CaCl}_{2} \times \dfrac{\text{0.10 mol CaCl}_{2}}{\text{1 L CaCl}_{2}} = \text{0.030 mol CaCl}_{2}$

(ii) Moles of ions

CaCl₂(s) ⟶ Ca²⁺(aq) + 2Cl⁻(aq)

We get 3 mol of ions from 1 mol of CaCl₂

$\text{Moles of ions } = \text{0.030 mol CaCl}_{2} \times \dfrac{\text{3 mol ions}}{\text{1 mol CaCl}_{2}} = \text{0.090 mol ions}$

c) 200.0 mL of 0.10 M FeCl₃

(i) Moles of FeCl₃

$\text{ Moles of FeCl}_{3} =\text{0.2000 L FeCl}_{3} \times \dfrac{\text{0.10 mol FeCl}_{3}}{\text{1 L FeCl}_{3}} = \text{0.020 mol FeCl}_{3}$

(ii) Moles of ions

FeCl₂(s) ⟶Fe³⁺(aq) + 3Cl⁻(aq)

We get 4 mol of ions from 1 mol of FeCl₃

$\text{ Moles of FeCl}_{3} =\text{0.2000 L FeCl}_{3} \times \dfrac{\text{0.10 mol FeCl}_{3}}{\text{1 L FeCl}_{3}} = \text{0.020 mol FeCl}_{3}$

d) 200.0 mL of 0.10 M KBr

(i) Moles of KBr

$\text{ Moles of KBr} = \text{0.2000 L KBr} \times \dfrac{\text{0.10 mol KBr }}{\text{1 L KBr}} = \text{0.020 mol KBr}$

(ii) Moles of ions

KBr(s) ⟶ K⁺(aq) + Br⁻

We get 2 mol of ions from 1 mol of KBr

$\text{Moles of ions } = \text{0.020 mol KBr} \times \dfrac{\text{2 mol ions}}{\text{1 mol KBr}} = \text{0.040 mol ions}\\\\\text{We get the most ions ions from }\boxed{\textbf{300.0 mL of 0.10 mol/L CaCl}_{2}}$

8 0

3 years ago

Why are firetrucks red

ivann1987 [24]

Because they are easier to see, I guess.

7 0

3 years ago

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