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Answer:
The answer to your question is 15500 mg of MgSO₄ 7H₂O
Explanation:
Data
Volume = 30 ml
Concentration = 0.3 M
Formula MgSO4∗7H2O
Process
1.- Calculate the number of moles needed
Molarity = moles / volume
Solve for moles
moles = Molarity x volume
Substitution
moles = 0.3 x 0.03 l
moles = 0.009 moles of MgSO₄
2.- Calculate the molecular mass of MgSO4∗7H2O
molecular mass = 24 + 32 + 64 + 14 + 112
= 246 g
3.- Get the proportion MgSO4 :7H2O, this proportion is 1 : 7
4.- Calculate the amount of MgSO4∗7H2O
![0.009 mol of MgSO4 \frac{7 MgSO4 7H2O}{1 mol MgSO4} \frac{246 g MgSO4 7H2O}{1 mol MgSO4 7H2O}](https://tex.z-dn.net/?f=0.009%20mol%20of%20MgSO4%20%5Cfrac%7B7%20MgSO4%207H2O%7D%7B1%20mol%20MgSO4%7D%20%5Cfrac%7B246%20g%20MgSO4%207H2O%7D%7B1%20mol%20MgSO4%207H2O%7D)
Simplification
15.5 g = 15500 mg
Answer:
Explanation:
Strong electrolytes completely ionize when dissolved, and no neutral molecules are formed in solution. Since NaCl is an ionic solid (s), which consists of cations Na+ and anions Cl−, no molecules of NaCl are present in NaCl solid or NaCl solution. The ionization is said to be complete.