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Svetlanka [38]
3 years ago
5

Dimensional analysis, Plz hell I don’t understand and plz explain

Chemistry
1 answer:
Anastasy [175]3 years ago
7 0

Explanation:

30 lb is 480 ounces

34 mi/second is 54.718 kilometre/ second

455 lb/ gal is 54521.024 grams / litre

50 cl is 500 millilitres

55nm is 5.5 × 10^-6 centimetre

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If a drop of blood is 0.05 mL, how many drops of blood are in a blood collection tube that holds 8 mL ?
inn [45]
160 drops of blood is needed 
6 0
3 years ago
Read 2 more answers
What do you think happens to the bonds between atoms when substances melt?
Eduardwww [97]

Answer:

As a substance melts, and goes from a solid to a liquid state, the kinetic energy of the molecules increases, and the molecules move faster, and they separate further and further away from each other.  The intermolecluar forces holding the molecules together become weaker.  This is why a liquid can take fill the shape of its container, whereas a solid has a fixed shape.

Explanation:

take your notes man

6 0
3 years ago
Identify what type of reaction is below. Also determine what coefficients that would balance the chemical equation. ___ HCl + __
egoroff_w [7]

Answer:

Single Replacement; 2, 1, 1, 1

Explanation:

2HCl + Zn → H2 + ZnCl2

In a single replacement reaction, one specie is replaced by another specie in a chemical reaction.

If we look at the reaction above, zinc metal reacted with hydrochloric acid. The reaction proceeds in such a manner that zinc replaces hydrogen in hydrochloric acid. This is a single replacement reaction because only one chemical specie is displaced in the reaction.

6 0
3 years ago
How many moles of O₂ are needed to burn 2.5 moles of CH₃OH?
IrinaK [193]

Answer:

3.75 moles

Explanation:

The chemical equation is 2CH₃OH + 3O₂ -> 2CO₂ + 4H₂O

2 moles of CH₃OH are burned by 3 moles of O₂

For 2.5 moles of CH₃OH are burned by x moles of O₂

Let's solve for x :

2*x=2.5*3 => 2*x=7.5 => x=3.75 moles of O₂ are needed to burn 2.5 moles of CH₃OH

5 0
3 years ago
Select True or False: A mixture made from 10 mL of 1 M HCl and 20 mL of 1 M CH3COONa would be classified as a buffer solution.
DIA [1.3K]

Answer:

True.

Explanation:

There are three ways to make a buffer.

a.  Generating a solution of a weak acid and its conjugate base.

b. Adding to a solution of a weak acid a certain quantity of

strong base, so that the acid remains in excess.

c. adding a limited amount to a conjugate base solution

of strong acid so that the base remains in excess.

We are in c, in this situation.

How do you calculate, pH? We apply Henderson Hasselbach.

pH = pka + log (mmoles base - mmoles acid)/ mmoles acid

pH = pKa + log ((20 ml . 1 M - 1 ml . 10M) / 10 mmoles

pH = 4.76 + log 1 → 4.76 ⇒ pH = pKa

8 0
3 years ago
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