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natta225 [31]
2 years ago
6

A jar contains only​ pennies, nickels,​ dimes, and quarters. There are 16 ​pennies, 18 ​dimes, and 28 quarters. The rest of the

coins are nickels. There are 84 coins in all. How many of the coins are not​ nickels? If n represents the number of nickels in the​ jar, what equation could you use to find​ n?
Mathematics
2 answers:
mario62 [17]2 years ago
8 0

Answer:

84 - (28+16+18)= n

Step-by-step explanation:

The parentheses are how many of the coins are not nickels. and if you add it then subtract it from the total amount you will get how many nickels were in the jar.

tatyana61 [14]2 years ago
6 0

Answer:

I hope this helps you

Step-by-step explanation:

84-16=68

68-18=50

50-28=22

n=22

equation:84-(16+18+28)

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The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

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The given quadratic equation is 24x^2 + 2x = 15

Let's rearrange the equation

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The equation or formula of quadratic formula is given as

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y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}

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