Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity =
1.500 M =
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of to grams of . As, the molar mass of is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.
If you could explain what “merkels” are, the question would be more clear.
Equilibrium is dynamic since the reaction never really stops. There is still a forward and reverse reaction, their rates are just equal to each other so there is no observable change in the amounts of product or reactant making it look like the reaction has stopped.
This is why you will often here the term dynamic equilibrium used when describing a system in equilibrium.
I hope this helps. Let me know if anything is unclear.