2. In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] =

Question

Misha Larkins [42]

3 years ago

11

2. In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] =

1.3 M. What is the equilibrium constant Kc for this reaction?
A. 0.064
B. 0.088
C. 0.114
D. 0.193

Chemistry

2 answers:

notsponge [240] · Answer 1 · 2022-04-03T08:01:14+03:00

notsponge [240]3 years ago

4 0

Kc= concentration of product divided by concentration of reactant
NO + NO2 ----> N2O3

Kc =(N2O3) / (No)(NO2)

Kc= ( 1.3 )/{ (3.9)(3.8) }

Kc=0.088 ( answer B)

Natali5045456 [20] · Answer 2 · 2022-04-03T09:56:52+03:00

Natali5045456 [20]3 years ago

4 0

Answer:

B. 0.088

Explanation:

I got it right