Question

2. In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] = 1.3 M. What is the equilibrium constant Kc for this reaction?
A. 0.064
B. 0.088
C. 0.114
D. 0.193

Answer 1

Kc= concentration  of  product  divided  by  concentration   of  reactant
NO +  NO2  ---->  N2O3

Kc =(N2O3)  /  (No)(NO2)

Kc= ( 1.3  )/{ (3.9)(3.8) }

Kc=0.088 (  answer  B)

Answer 2

Answer:

B. 0.088

Explanation:

I got it right