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Misha Larkins [42]
3 years ago
11

2. In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] =

1.3 M. What is the equilibrium constant Kc for this reaction?
A. 0.064
B. 0.088
C. 0.114
D. 0.193
Chemistry
2 answers:
notsponge [240]3 years ago
4 0
Kc= concentration  of  product  divided  by  concentration   of  reactant
NO +  NO2  ---->  N2O3

Kc =(N2O3)  /  (No)(NO2)

Kc= ( 1.3  )/{ (3.9)(3.8) }

Kc=0.088 (  answer  B)
Natali5045456 [20]3 years ago
4 0

Answer:

B. 0.088

Explanation:

I got it right

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Answer:

\boxed {\boxed {\sf 0.80 \ mol\ F}}

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We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

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4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}

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4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}

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\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F

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0.80 \ mol \ F

4.8 × 10²³ fluorine atoms are equal to <u>0.80 moles of fluorine.</u>

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