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Misha Larkins [42]
3 years ago
11

2. In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] =

1.3 M. What is the equilibrium constant Kc for this reaction?
A. 0.064
B. 0.088
C. 0.114
D. 0.193
Chemistry
2 answers:
notsponge [240]3 years ago
4 0
Kc= concentration  of  product  divided  by  concentration   of  reactant
NO +  NO2  ---->  N2O3

Kc =(N2O3)  /  (No)(NO2)

Kc= ( 1.3  )/{ (3.9)(3.8) }

Kc=0.088 (  answer  B)
Natali5045456 [20]3 years ago
4 0

Answer:

B. 0.088

Explanation:

I got it right

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Calculate the number of atoms in 0.25 moles of manganese?
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<h3>Answer:</h3>

1.5 × 10²³ atoms Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.25 mol Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 0.25 \ mol \ Mn(\frac{6.022 \cdot 10^{23} \ atoms \ Mn}{1 \ mol \ Mn})
  2. Multiply:                            \displaystyle 1.5055 \cdot 10^{23} \ atoms \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.5055 × 10²³ atoms Mn ≈ 1.5 × 10²³ atoms Mn

3 0
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The answer to number 1 is D
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