Calcula la energia cinetica de un cohete de 500kg de masa que se mueve a una velocidad de 27.8m/s
1 answer:
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Answer:
⇒ We have Na2O + H2O --> NaOH. We have 2 sodiums and 2 oxygens and 2 hydrogens on the left side, but only one of each on the right side.
Sodium Oxide + Water → Sodium Hydroxide
⇒ Na2O + H2O → 2NaOH .
Sodium oxide is used in ceramics and glasses. Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution.
This is an incomplete question, here is a complete question.
Consider the following equilibrium at 100°C.
Concentration at equilibrium:
If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?
Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.
Explanation :
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
The expression for reaction quotient will be :
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Now put all the given values in this expression, we get
The given equilibrium constant value is,
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
There are 3 conditions:
When that means product > reactant. So, the reaction is reactant favored.
When that means reactant > product. So, the reaction is product favored.
When that means product = reactant. So, the reaction is in equilibrium.
From the above we conclude that, the that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.
Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.
Answer: 4.4 x 10^-7
Explanation:
The dissociation equation for this reaction is:
MgCO3 (s) → Mg+2 (aq) + CO3-2 (aq)
(Here 0.08 >>> x )
So the solubility MgCO₃ in a solution that containing 0.080 M Mg²⁺ is 4.4 x 10^-7