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riadik2000 [5.3K]
4 years ago
14

Difference between compounds and mixtures. How do you separate them

Chemistry
2 answers:
hram777 [196]4 years ago
5 0
♥ Mixture refers to any substance which is composed of molecules of different types.
♥ The different elements and compounds in the mixture retain their original physical properties even after combining to form a mixture.
Mandarinka [93]4 years ago
4 0
Mixture- each substance stays the same
Compound - has properties different from the elements.

However with a compound a chemical reaction is required to separate them but a mixture is easily to separate.
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No. of valence electron determine the reaction between elements.
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Which of the following statements holds true for a chemical change?
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2 years ago
A chemistry graduate student is given 125.mL of a 0.20M acetic acid HCH3CO2 solution. Acetic acid is a weak acid with =Ka×1.810−
Over [174]

Answer : The mass of sodium acetate is, 1.097 grams.

Explanation : Given,

The dissociation constant for acetic acid = K_a=1.8\times 10^{-5}

Concentration of acetic acid (weak acid)= 0.20 M

volume of solution = 125. mL

pH = 4.47

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.8\times 10^{-5})

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pK_a=4.74

Now we have to calculate the concentration of sodium acetate (conjugate base or salt).

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

4.47=4.74+\log (\frac{[Salt]}{0.20})

[Salt]=0.107M

Now we have to calculate the mass of sodium acetate.

\text{Concentration}=\frac{\text{Mass of }NaCH_3CO_2\times 1000}{\text{Molar mass of }NaCH_3CO_2\times \text{Volume of solution (in mL)}}

0.107M=\frac{\text{Mass of }NaCH_3CO_2\times 1000}{82g/mol\times 125mL}

\text{Mass of }NaCH_3CO_2=1.097g

Therefore, the mass of sodium acetate is, 1.097 grams.

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4 years ago
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Answer:

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Among these techniques is the measurement of appearance of products.

This means we have;

Rate of reaction = Rate of appearance of product

Hence;

Rate of reaction = 2.0 M/s

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How did the concentration of iodide ions change in these two trials, how did the rate change accordingly?
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