Difference between compounds and mixtures. How do you separate them

2 answers:

5 0

♥ Mixture refers to any substance which is composed of molecules of different types.
♥ The different elements and compounds in the mixture retain their original physical properties even after combining to form a mixture.

Mandarinka [93]3 years ago

4 0

Mixture- each substance stays the same
Compound - has properties different from the elements.

However with a compound a chemical reaction is required to separate them but a mixture is easily to separate.

You might be interested in

40 cm3 of acid were mixed with 60 cm3 of alkali in an insulated container. What name is given to this type of reaction?

Stells [14]

Answer:

neutralization reaction

6 0

2 years ago

HBrO3 <br> A. All non metals “acid subcategory”

Irina-Kira [14]

Non metals acid subcategories

4 0

3 years ago

Chemicals that are able to slow or stop the reaction rate are inhibitors. reactants. products. catalysts.

erma4kov [3.2K]

Answer:inhibitors

Explanation:

I just took the quiz .

7 0

3 years ago

Read 2 more answers

A gas container has a volume of 446.9 with a temp of 14c. When the volume is decreased to 238.7l the new temp is what

swat32

Answer:

$\frac{V _{1}}{T _{1}} = \frac{V _{2}}{T _{2} } \\ \frac{446.9}{(14 + 273)} = \frac{238.7}{T _{2} } \\ {T _{2}} = \frac{238.7 \times 287}{446.9} \\ {T _{2}} = 153.3 \: kelvin \\ = 119.7 \degree \: c$

7 0

3 years ago

Each student in a class placed a 2.00 g sample of a mixture of Cu and Al in a beaker and placed the beaker in a fume hood. The s

Aleks [24]

Answer:

Percentage mass of copper in the sample = 32%

Explanation:

Equation of the reaction producing Cu(NO₃) is given below:

Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)

From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.

Molar mass of copper = 64 g/mol

mass of copper = number of moles * molar mass

mass of copper = 0.01 mol * 64 g/mol = 0.64 g

Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%

Percentage mass of copper in the sample = 32%

3 0

3 years ago