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kari74 [83]
2 years ago
8

Which factor has the least effect on the rate of solution of a solid in a liquid?

Chemistry
2 answers:
vitfil [10]2 years ago
4 0
The pressure will not affect the rate of solution.
ziro4ka [17]2 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

Since, the substance added is a solid and particles of a solid are very closely held to each other because of strong intermolecular forces of attraction between them.

This makes them to have a definite shape and volume. Therefore, when pressure is applied on a solid then its particles will be least affected by it as they are already close to each other.

Whereas stirring, amount of surface area, and temperature will equally affect the rate of dissolution of the solid.

Hence, we can conclude that pressure is the factor that has least effect on the rate of solution of a solid in a liquid.

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Given any two elements within a group, is the element with the larger atomic number likely to have a larger or smaller atomic ra
zhenek [66]

Answer:

Atomic radius of sodium = 227 pm

Atomic radius of potassium = 280 pm

Explanation:

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

Consider the example of sodium and potassium.

Sodium is present above the potassium with in same group i.e, group one.

The atomic number of sodium is 11 and potassium 19.

So potassium will have larger atomic radius as compared to sodium.

Atomic radius of sodium = 227 pm

Atomic radius of potassium = 280 pm

3 0
3 years ago
Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).
Artemon [7]

Answer:

5.9x10^-2 M

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Concentration of CO, [CO] = 0.30 M

Concentration of H2, [H2] = 0.10 M

Concentration of H2O, [H2O] = 0.020 M

Equilibrium constant, K = 3.90

Concentration of CH4, [CH4] =..?

Step 2:

The balanced equation for the reaction. This is given below:

CO(g) + 3H2(g) <=> CH4(g) + H2O(g)

Step 3:

Determination of the concentration of CH4.

The expression for equilibrium constant of the above equation is given below:

K = [CH4] [H2O] / [CO] [H2]^3

3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3

Cross multiply to express in linear form

[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3

Divide both side by 0.02

[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02

[CH4] = 5.9x10^-2 M

Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M

5 0
2 years ago
In addition to displacing halide ions, the acetylide ion also adds to carbonyl groups. 2-Methyl-3-butyn-2-ol (MBI) is an acetyle
Veronika [31]

Answer:

Explanation:

check below for explanation.

8 0
3 years ago
Which of these is an environmental effect of building dams?
nadezda [96]
Hmm... I'm unsure but its either B or D.
7 0
3 years ago
Read 2 more answers
How many moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm?
marshall27 [118]

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

Mole is the unit of amount of substances of specified elementary entities

According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation

n =pV/RT

Here given data is volume = 87.1 liters

Temperature = 74 °C means 347.15 k

Pressure = 3.5 atm

R = 0.0821

Putting this value in ideal gas equation then

n =pV/RT

n =  3.5 atm×87.1 liters / 0.0821 ×347.15 k

n = 021.65 mole

Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is  021.65 mole

Know more about mole of helium

brainly.com/question/23365554

#SPJ1

8 0
9 months ago
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