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earnstyle [38]
3 years ago
12

Please answer this questions

Mathematics
1 answer:
yan [13]3 years ago
6 0

Answer:

4

Step-by-step explanation:

It's going backwards by two

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what property could you used to show that the distance between the elephants and giraffes is the same as the distance between th
Nadya [2.5K]

There are several algebraic properties of equality.

<em>The property that shows that both distance are the equal is the symmetric property of equality</em>

Represent the distance between the elephants and the giraffes with x

Represent the distance between the tigers and the zebras with y

The symmetric property of equality states that:

<em>For 2 expressions or numbers; x and y</em>

<em>If x = y, then y = x</em>

<em />

<em />

<em />

In this context, the above property means that:

<em>If the distance between the elephants and the giraffes is the same as the distance between the tigers and the zebras, then both distance are equal</em>

<em />

Hence, the property to use is the symmetric property of equality

Read more about properties of equality at:

brainly.com/question/13130806

3 0
2 years ago
Help no links please u^u
Veseljchak [2.6K]

Answer:

∠A= 80°

Step-by-step explanation:

if they are supplementary then put them equal to 180

7x + 3 +7x + 23 = 180

14x + 26 = 180

14x = 154

x= 11

now plug in

7(11)+3

77+3= 80

3 0
3 years ago
Which is equal to 10^12/10^-3
tiny-mole [99]
10^[ 12 - ( - 3 ) ] = 10^( 12 + 3 ) = 10^15 ;
We use the formula
:
3 0
3 years ago
How do I do this problem?
klemol [59]

Step-by-step explanation:

here is the answer to your question

7 0
2 years ago
Read 2 more answers
If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how
Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em>1.85 \times 10^{10}<em> liters each year</em>

Given

Cars = 1.8\ million

d = 17500km --- distance

r = 40miles/gallon

First, we calculate the number (n) of gallons used by each car

r = \frac{d}{n}

Solve for n

n = \frac{d}{r}

So, we have:

n = \frac{17500km}{40miles/gallon}

n = \frac{17500km}{40miles}gallon

Convert miles to kilometers

n = \frac{17500km}{40km \times 1.60934}gallon

n = \frac{17500km}{64.3738km}gallon

n = 271.85\ gallon

The number of gallons (N), used by all the cars is:

N = n \times cars

N = 271.85 \times 1.8\ million

N = 489330000

Convert to liters

N = 489330000 \times 3.78541L

N = 1852314675.3L

In scientific notation to 2 decimal places, we have:

N = 1.85 \times 10^{10}L

<em>Hence, the number of liters used is </em>1.85 \times 10^{10}<em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0
3 years ago
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