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earnstyle [38]
3 years ago
12

Please answer this questions

Mathematics
1 answer:
yan [13]3 years ago
6 0

Answer:

4

Step-by-step explanation:

It's going backwards by two

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PLEASE HELP ASAP STUDY GUIDE DUE IN TWO HOURS!!!!!!
Finger [1]

Answer:

Fourth degree polynomial (aka: quartic)

====================================================

Work Shown:

There isnt much work to show here because we can use the fundamental theorem of algebra. The fundamental theorem of algebra states that the number of roots is directly equal to the degree. So if we have 4 roots, then the degree is 4. This is assuming that there are no complex or imaginary roots.

-------------------

If you want to show more work, then you would effectively expand out the polynomial

(x-m)(x-n)(x-p)(x-q)

where

m = 4, n = 2, p = sqrt(2), q = -sqrt(2)

are the four roots in question

(x-m)(x-n)(x-p)(x-q)

(x-4)(x-2)(x-sqrt(2))(x-(-sqrt(2)))

(x-4)(x-2)(x-sqrt(2))(x+sqrt(2))

(x^2-6x+8)(x^2 - 2)

(x^2-2)(x^2-6x+8)

x^2(x^2-6x+8) - 2(x^2-6x+8)

x^4-6x^3+8x^2 - 2x^2 + 12x - 16

x^4 - 6x^3 + 6x^2 + 12x - 16

We end up with a 4th degree polynomial since the largest exponent is 4.

3 0
3 years ago
HELP PLEASE!!! WORTH 8 points!!!!
vichka [17]
It seem like it's listing the factors and not the roots. If the given factors are x-2, x-(1+sqrt(5)), and x+3i

Then this means that x-(1-sqrt(5)) is another factor. So it looks like choice B is the answer. I'm using the idea that if x-(a+b*sqrt(c)) is a factor then so is x-(a-b*sqrt(c)). 
7 0
3 years ago
Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi
umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

6 1
3 years ago
Read 2 more answers
I need help asap:):):)
Elena L [17]

Answer:

10 feet

Step-by-step explanation:

18 × 2 = 36

56 - 36 = 20

20 ÷ 2 = 10

To check work, add all lengths together. 4 sides. 18 + 18 + 10 + 10 = 56

6 0
3 years ago
Read 2 more answers
(13+29-2)÷2<br> show your work​
olga55 [171]

Answer:

(13 + 29 - 2) \div 2 \\ (42 -2 ) \div 2 \\ 40 \div 2 \\  = 20

7 0
3 years ago
Read 2 more answers
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