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Paul [167]
3 years ago
13

Jill formed ionic compounds using the index cards she combined sodium and zinc to form the compound na2zn is this a possible a i

onic compound and why
Chemistry
1 answer:
expeople1 [14]3 years ago
5 0
<span>No. Zn can only have oxidation states of 1+ or 2+. For this compound to be able to exist, the Zn would have to have an oxidation state of 2- to counteract the 2+ from the 2 sodium ions. Sodium ions each have a +1 charge, so the 2 sodium ions would carry a +2 charge. In order for the compound to exist, the net charge between the 2 sodium and 1 zinc atoms would need to be 0.</span>
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a lung is NOT an organism.
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2 years ago
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Identify the formula of the precipitate formed when solutions of sodium perchlorate and nickel(II) nitrate are mixed. If no prec
kumpel [21]

Answer:

2NaClO₄ (aq) + Ni(NO₃)₂ (aq)  → 2NaNO₃ (aq) + Ni(ClO₄)₂ (aq)

No reaction

Explanation:

NaClO₄ → Sodium perchlorate

Ni(NO₃)₂ →  Nickel (II) nitrate

All the salts from nitrate are soluble salts

All the salts from perchlorate are soluble salts except for the KClO₄

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3 years ago
Determine the identity of a cube of metal that measures 1.2 cm on each side and has a mass of 15.4g.
FromTheMoon [43]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
density 15.4 grams per 1.2³ cm³ ≅ 8.9 grams per cm³ 
<span>Find the metal that has a density of approximately 8.9 g/cm³</span>
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3 years ago
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A thermometer having first-order dynamics with a time constant of 1 min is placed in a temperature bath at 100oF. After the ther
sveticcg [70]

Answer:

(a) See below

(b) 103.935 °F; 102.235 °F

Explanation:

The equation relating the temperature to time is

T = T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )

1. Calculate the thermometer readings after  0.5 min and 1 min

(a) After 0.5 min

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-0.5/1} \right )\\ & = & 100 + 10\left (1 - e^{-0.5} \right )\\ & = & 100 + 10 (1 - 0.6065)\\ & = & 100 + 10(0.3935)\\ & = & 100 + 3.935\\ & = & 103.935\,^{\circ}F\\\end{array}

(b) After 1 min

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-t/\tau} \right )\\ & = & 100 + 10\left (1 - e^{-1/1} \right )\\ & = & 100 + 10\left (1 - e^{-1} \right )\\ & = & 100 + 10 (1 - 0.3679)\\ & = & 100 + 10(0.6321)\\ & = & 100 + 6.321\\ & = & 106.321\,^{\circ}F\\\end{array}

2. Calculate the thermometer reading after 2.0 min

T₀ =106.321 °F

ΔT = 100 - 106.321 °F = -6.321 °F

  t = t - 1, because the cooling starts 1 min late

\begin{array}{rcl}T & = & T_{0} + \Delta T\left (1 - e^{-(t - 1)/\tau} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-(2 - 1)/1} \right )\\ & = & 106.321 - 6.321\left (1 - e^{-1} \right )\\ & = & 106.321 - 6.321 (1 - 0.3679)\\ & = & 106.321 - 6.321 (0.6321)\\ & = & 106.321 - 3.996\\ & = & 102.325\,^{\circ}F\\\end{array}

3. Plot the temperature readings as a function of time.

The graphs are shown below.

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3 years ago
Write the symbol for every chemical element that has atomic number greater than 55 and atomic mass less than 144.0 u
laila [671]
You will need a periodic table to help you answer this problem. The atomic numbers are arrange from lowest to highest in the periodic table. You can locate element number 55 to be Cesium with an atomic weight of 132.905 amu. So, you start from element 56. The following elements are:

56     Barium       137.328 amu
57     Lanthanium   138.905 amu
58     Cerium       140.116 amu
59     <span>Praseodymium    140.908 amu
60     Neodymium   144.243 amu

Neodymium is already greater than 144 amu. Therefore, these elements only include Barium, Lanthanium, Cerium and Praseodymium.</span>
3 0
3 years ago
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