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jeka94
3 years ago
14

Find the greatest common factor of 6y^3 and 10n^2

Mathematics
1 answer:
Tasya [4]3 years ago
7 0
SOLUTION:

GCF = 2

= 6y^3 + 10n^2

= 2 ( 3y^3 + 5n^2 )

Hope this helps! :)
Have a lovely day! <3
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The height of a triangle is 5 m less than its base. The area of the triangle is 42 m².
SCORPION-xisa [38]
A = (1/2) b * h
h = b - 5
42 = (1/2) * b * (b - 5)
42 = (1/2) * b^2 - 5b
multiply both sides by 2 to clear the fraction (1/2)
2(42) = 2(1/2) *b^2 - 5b
84 = b^2 -5b
Since this is a quadratic equation, subtract 84 from both sides so that it is set = to zero.
b^2 - 5b - 84 = 0
Now factor.
(b - 12)(b + 5) = 0
b - 12 = 0; b = 12
b + 5 = 0; b = -5
You can't have a negative length so the answer is 12m
To check the answer:
A = (1/2) * 12* 7
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4 0
3 years ago
Find the length of Arc YWV, if line XZ=12 meters. (Round to the nearest hundredth)
Oksana_A [137]

Answer:

53.62 m

Step-by-step explanation:

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r = XZ = 12 m

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θ = 85° + 72° + 108° = 265°

Length of arc YWV = 256/360 × 2 × π × 12

= 53.6165146 ≈ 53.62 m (nearest hundredth)

3 0
3 years ago
Use the parabola tool to graph the quadratic function. f(x)=2x^2 +12x+16 Graph the parabola by first plotting its vertex and the
givi [52]
(-3, -2) is the vertex. 

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Korolek [52]
I think the best possibility that could lead Aiden's mistake are the following, First, it must be that the length of the paper strips are not the same. Second, it would be that she miscounted the strips. I hope you are satisfied with my answer and feel free to ask for more 
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3 years ago
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What is 20% of 148<br> Anyone know
Alexeev081 [22]

Answer:

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Step-by-step explanation:

20% = 0.20

0.20 * 148 = 29.6

6 0
3 years ago
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