All categories

3 years ago

HELP URGENT!! EDGINUITY!!

Mathematics

1 answer:

Nataliya [291]3 years ago

7 0

Hello from MrBillDoesMath!

Answer:

The first choice (2x + 4y >=3, 2x +4y <=3)

Discussion:

Suppose a variable M met these conditions: M >=3 and M <=3. The only way this can happen is that M = 3. In our case letting M = 2x + 4y, we find the inequalities give

2x + 4y = 3

which is the equation of a line. (The other choices do NOT include the boundary line because they use strict < or > signs.)

Thank you,

MrB

You might be interested in

Can help my little bro

lisabon 2012 [21]

Answer:

$0.03

Step-by-step explanation:

chips: 7.84/16=0.49

pretzels: 12.48/24=0.52

0.52=0.49=0.03

7 0

2 years ago

Find the missing side of the triangle

slamgirl [31]

Answer:

the answer would be 11.62

Step-by-step explanation:

16^2 -11^2= 11.62^2

4 0

3 years ago

at the library, you find 9 books on a certain topic. the librarian tells you that 55% of the books on this topic have been signe

e-lub [12.9K]

Multiply 9 books by 55% by doing

9 x .55 = 4.95

We can't have 4.95 books, though so it rounds down to 4 because you can't just add another .05.

8 0

3 years ago

Help please .............................

Rufina [12.5K]

Answer:I think its the second one

Step-by-step explanation:

7 0

2 years ago

Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic

Andrei [34K]

Answer:

$\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

$(x-a)^2+(y-b)^2+(z-c)^2=r^2$

Where ( $x,y,z$ ) are the points on sphere.

$(a, b, c)$ is the center of the sphere and

$r$ is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here,

$x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3$

So, Radius is:

$r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}$

Therefore the equation of the sphere is:

$(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

4 0

3 years ago